从响应NSString获取子字符串

时间:2013-03-21 07:01:24

标签: iphone ios nsstring

我需要从字符串

获取子串CODE的值(X2.31
NSString *str = @"SHMU=\"\" CODE=\"X2.31\" XTN=\";

我怎样才能获得特定的子字符串?

3 个答案:

答案 0 :(得分:1)

尝试以下

  NSString *str = @"SHMU=\"\" CODE=\"X2.31\" XTN=\"";

 NSRange range = [str rangeOfString:@"CODE="];
 NSString *substring = [[str substringFromIndex:NSMaxRange(range)] stringByTrimmingCharactersInSet:[NSCharacterSet whitespaceCharacterSet]];
 NSArray *str1 = [substring componentsSeparatedByString:@" "];
 NSLog(@"the sub %@",[[str1 objectAtIndex:0] stringByTrimmingCharactersInSet[NSCharacterSet whitespaceCharacterSet]]);

字符串是“X2.31”

答案 1 :(得分:0)

NSString *strOrg = [NSString stringWithFormat:@"%@",@"SHMU=\"\" CODE=\"X2.31\" XTN=\""] ;

NSString *strLeft = [NSString stringWithFormat:@"%@",@"SHMU=\"\" CODE=\""] ;
NSString *strRight = [NSString stringWithFormat:@"%@",@"\" XTN=\""] ;

NSLog(@"%@", [self getDataBetweenString:strOrg LeftString:strLeft RightString:strRight LeftOffset:13]);

- (NSString *)getDataBetweenString:(NSString *)orgString LeftString:(NSString *)leftString RightString:(NSString *)rightString LeftOffset:(NSInteger)leftPos;
{
    NSInteger left, right;
    NSString *foundData;
    NSScanner *scanner=[NSScanner scannerWithString:orgString];
    [scanner scanUpToString:leftString intoString: nil];
    left = [scanner scanLocation];
    [scanner setScanLocation:left + leftPos];
    [scanner scanUpToString:rightString intoString: nil];
    right = [scanner scanLocation] + 1;
    left += leftPos;
    foundData = [orgString substringWithRange: NSMakeRange(left, (right - left) - 1)];         return foundData;
}

答案 2 :(得分:0)

这只是您发布的 str 特定。 您的号码必须紧跟First X.

float f=[[str componentsSeparatedByString:@"X"][1] floatValue];