我的mySQL数据库中有2个表:
while True:
print "Please choose from one of the five following options:"
print " 1. 10^1\n 2. 10^2\n 3. 10^3\n 4. 10^4\n 5. 10^5\n"
choice = raw_input()
if choice == 1:
print "1"
elif choice == 2:
print "2"
elif choice == 3:
print "3"
elif choice == 4:
print "4"
elif choice == 5:
print "5"
else:
print "Not a valid choice!\n"
我需要一个返回类似内容的查询:
Table Sensor
_id Name
1 Sensor1
2 Sensor2
Table History
_id Sensor_fk Date
1 1 2015-05-24
2 2 2015-05-27
3 1 2015-05-28
4 1 2015-05-28
5 2 2015-05-28
...
这是按日期分组的2个传感器的数量。我将用这些数据填充条形图。 有人可以帮帮我吗?
答案 0 :(得分:0)
您需要为每个Sensor的两个单独的GROUP BY子句执行UNION。像
(Select count(*) as Sensor1 from History h
where h.Sensor_FK = 1
group by DateField
)
Union
(Select Count(*) as Sensor2 from History h
whre h.Sensor_FK = 2
group by DateField
)
答案 1 :(得分:0)
我明白了。
SELECT h.date as Date,
count(CASE WHEN h.sensor_fk = 1 THEN h.sensor_fk END) as 'Sensor1',
count(CASE WHEN h.sensor_fk = 2 THEN h.sensor_fk END) as 'Sensor2'
FROM history h
GROUP BY Date