Question

我在MySQL表中有以下数据：

+-------------------------------------+-----------------+
|            DATE                     | SipResponseCode |
+-------------------------------------+-----------------+
| 20 Feb                              |             200 |
| 20 Feb                              |             500 |
| 20 Feb                              |             200 |
| 20 Feb                              |             200 |
| 20 Feb                              |             487 |
| 20 Feb                              |             200 |
| 20 Feb                              |             200 |
| 20 Feb                              |             500 |
| 20 Feb                              |             500 |
| 20 Feb                              |             487 |
| 20 Feb                              |             200 |
| 20 Feb                              |             200 |
| 20 Feb                              |             200 |
| 20 Feb                              |             500 |
| 20 Feb                              |             200 |
| 20 Feb                              |             200 |
| 20 Feb                              |             200 |
| 20 Feb                              |             200 |
| 20 Feb                              |             200 |
| 20 Feb                              |             500 |
| 21 Feb                              |             200 |
| 21 Feb                              |             487 |
| 21 Feb                              |             200 |
| 21 Feb                              |             487 |
| 21 Feb                              |             487 |
| 21 Feb                              |             487 |
| 21 Feb                              |             487 |
| 21 Feb                              |             200 |
| 21 Feb                              |             200 |
| 21 Feb                              |             487 |
| 21 Feb                              |             487 |
| 21 Feb                              |             500 |

我想编写SQL查询，以便它可以计算每天的SipResponseCode数200，487，500

+-------------------------------------+------------+-----------+--------+
|            DATE                     |    200     |    487    |   500  |
+-------------------------------------+------------+--------------------+
| 20 Feb                              |     14     |      2    |    5   |
| 21 Feb                              |     4      |      7    |    1   |

我已经累了但无法得到正确的结果。

Answer 1

如果值200,487和500是您在编写查询时知道的常量值，则可以在select子句的case语句中使用它们。

比case语句更具可读性的东西是使用带有条件的SUM（）函数，它基本上会计算满足该条件的行数。试试这个：

SELECT dateColumn, 
   SUM(SisResponseCode = 200) AS '200', 
   SUM(SisResponseCode = 487) AS '487', 
   SUM(SisResponseCode = 500) AS '500'
FROM myTable
GROUP BY dateColumn;

Answer 2

以下查询将为您提供结果，而不是您想要的结果，但稍后可以通过您的语言（PHP，C＃等）轻松解析它。

SELECT  DATE, GROUP_CONCAT(CAST(TEST AS CHAR(10000) CHARACTER SET utf8) SEPARATOR ",") AS myCol
FROM
(
    SELECT      DATE, CONCAT(SipResponseCode, "^",  COUNT(*)) AS TEST
    FROM        table1
    GROUP BY    DATE, SipResponseCode
) a
GROUP BY DATE

Answer 3

标准答案大致如下：

SELECT date
     , sipresponsecode
     , COUNT(sipresponsecode) x 
  FROM my_table 
 GROUP 
    BY date
     , sipresponsecode;

MySQL查询计数每个日期/时间有多个组

3 个答案: