这是我的问题:
我正在使用Devise's guest_user,它包含一个logging_in方法,用于在登录时将guest_user参数传输给注册用户。所以在我的情况下,用户has_many periods, dependent: :destroy
,所以这里是logging_in方法:
def logging_in
guest_periods = guest_user.periods.all
guest_periods.each do |p|
p.user_id = current_user.id
p.save!
end
current_user.latest_entry = guest_user.latest_entry
current_user.is_in_zone = guest_user.is_in_zone
current_user.save
end
但是,当guest_user登录时,他的句点会被销毁而不是被转移。这是日志:
Started GET "/" for ::1 at 2015-05-11 00:18:03 +0300
Processing by WelcomeController#index as HTML
User Load (0.4ms) SELECT "users".* FROM "users" WHERE "users"."id" = $1 ORDER BY "users"."id" ASC LIMIT 1 [["id", 24]]
User Load (0.4ms) SELECT "users".* FROM "users" WHERE "users"."id" = $1 LIMIT 1 [["id", 23]]
Period Load (0.3ms) SELECT "periods".* FROM "periods" WHERE "periods"."user_id" = $1 [["user_id", 23]]
(0.2ms) BEGIN
CACHE (0.0ms) SELECT "periods".* FROM "periods" WHERE "periods"."user_id" = $1 [["user_id", 23]]
SQL (0.8ms) UPDATE "periods" SET "user_id" = $1, "updated_at" = $2 WHERE "periods"."id" = $3 [["user_id", 24], ["updated_at", "2015-05-10 21:18:03.863162"], ["id", 170]]
(0.9ms) COMMIT
(0.2ms) BEGIN
SQL (2.1ms) UPDATE "users" SET "is_in_zone" = $1, "latest_entry" = $2, "updated_at" = $3 WHERE "users"."id" = $4 [["is_in_zone", "t"], ["latest_entry", "2015-05-04"], ["updated_at", "2015-05-10 21:18:03.875572"], ["id", 24]]
(15.8ms) COMMIT
(0.5ms) BEGIN
SQL (0.3ms) DELETE FROM "periods" WHERE "periods"."id" = $1 [["id", 170]]
SQL (0.7ms) DELETE FROM "users" WHERE "users"."id" = $1 [["id", 23]]
(1.2ms) COMMIT
所以我们可以看到转移已经完成,但最后,无论如何都会破坏这些时期。它们不应该是,因为它们不再属于要被销毁的用户。
为什么会这样?
答案 0 :(得分:2)
即使Period#user_id
已更改,guest_user.periods
仍会在内存中加载,并且在销毁来宾用户时会被销毁。如果你guest_user.reload
,它的关联将清除,并且它可以安全地销毁。您还可以guest_user.periods(true)
强制重新加载句点。
另一种选择是:
guest_user.periods.update_all(user_id: current_user.id)
这会执行单个查询来执行更新,如果有很多句点会很好,并且也不会加载guest_user.periods
关联,所以它会在销毁期间加载新的并找到正确的空集。