我有一个英文字符串,可能有也可能没有数字。但我希望这些数字在屏幕上打印为波斯数字。
例如NSString *foo = @"a string with numbers 1 2 3;"
然后输出应为a string with numbers ۱۲۳
我现在使用的代码是:
-(NSString *)convertEnNumberToFarsi:(NSString *) number{
NSString *text;
NSDecimalNumber *someNumber = [NSDecimalNumber decimalNumberWithString:number];
NSNumberFormatter *formatter = [[NSNumberFormatter alloc] init];
NSLocale *gbLocale = [[NSLocale alloc] initWithLocaleIdentifier:@"fa"];
[formatter setLocale:gbLocale];
text = [formatter stringFromNumber:someNumber];
return text;
}
此方法仅转换仅包含数字的字符串,但如上所述,我想转换任何可能包含或不包含数字的字符串。
我怎样才能做到这一点?
答案 0 :(得分:8)
简单的方法:
NSDictionary *numbersDictionary = @{@"1" : @"۱", @"2" : @"۲", @"3" : @"۳", @"4" : @"۴", @"5" : @"۵", @"6" : @"۶", @"7" : @"۷", @"8" : @"۸", @"9" : @"۹"};
for (NSString *key in numbersDictionary) {
str = [str stringByReplacingOccurrencesOfString:key withString:numbersDictionary[key]];
}
使用区域设置更灵活的其他解决方案:
NSNumberFormatter *formatter = [NSNumberFormatter new];
formatter.locale = [NSLocale localeWithLocaleIdentifier:@"ar"];
for (NSInteger i = 0; i < 10; i++) {
NSNumber *num = @(i);
str = [str stringByReplacingOccurrencesOfString:num.stringValue withString:[formatter stringFromNumber:num]];
}
注意:此代码在没有IDE的情况下编写,可能会出现语法错误。
答案 1 :(得分:8)
在swift 3中:
func convertEngNumToPersianNum(num: String)->String{
let number = NSNumber(value: Int(num)!)
let format = NumberFormatter()
format.locale = Locale(identifier: "fa_IR")
let faNumber = format.string(from: number)
return faNumber!
}
强行打开前检查以防止崩溃。
答案 2 :(得分:4)
斯威夫特3:
然而,其他答案是正确的,将String
转换为Int
时存在一些问题。
将String
转换为Int
会删除不好的左零(特别是转换手机和国家ID)。为了避免这个问题,我更喜欢将每个英文编号替换为波斯语。
static func convertToPersian(text : String)-> String {
let numbersDictionary : Dictionary = ["0" : "۰","1" : "۱", "2" : "۲", "3" : "۳", "4" : "۴", "5" : "۵", "6" : "۶", "7" : "۷", "8" : "۸", "9" : "۹"]
var str : String = text
for (key,value) in numbersDictionary {
str = str.replacingOccurrences(of: key, with: value)
}
return str
}
此方法也可用于替换文本中的数字,而不必使用纯数字转换为波斯语。
答案 3 :(得分:1)
我担心除了更换它们之外别无他法。
e.g:
str =[str stringByReplacingOccurrencesOfString:@"0" withString:@"۰"];
.
.
.
答案 4 :(得分:1)
迅速5
func getNumerals(num: Int) -> String {
if getLanguage() == "ar" // You can set locale of your language
{
let number = NSNumber(value: num)
let format = NumberFormatter()
format.locale = Locale(identifier: "ar") // You can set locale of your language
let formatedNumber = format.string(from: number)
return formatedNumber!
} else {
return "\(num)"
}
}
答案 5 :(得分:1)
具有以下扩展名,您可以做到:
extension String {
private static let formatter = NumberFormatter()
func clippingCharacters(in characterSet: CharacterSet) -> String {
components(separatedBy: characterSet).joined()
}
func convertedDigitsToLocale(_ locale: Locale = .current) -> String {
let digits = Set(clippingCharacters(in: CharacterSet.decimalDigits.inverted))
guard !digits.isEmpty else { return self }
Self.formatter.locale = locale
let maps: [(original: String, converted: String)] = digits.map {
let original = String($0)
guard let digit = Self.formatter.number(from: String($0)) else {
assertionFailure("Can not convert to number from: \(original)")
return (original, original)
}
guard let localized = Self.formatter.string(from: digit) else {
assertionFailure("Can not convert to string from: \(digit)")
return (original, original)
}
return (original, localized)
}
var converted = self
for map in maps { converted = converted.replacingOccurrences(of: map.original, with: map.converted) }
return converted
}
}
"سلام 12345".convertedDigitsToLocale(Locale(identifier: "FA")) /* سلام ۱۲۳۴۵ */
"Hello ۱۲۳۴۵".convertedDigitsToLocale(Locale(identifier: "EN")) /* Hello 12345 */
答案 6 :(得分:0)
+(NSString *)convertNumToPersian:(NSString *)EnglishNumString
{
if ( [EnglishNumString isEqual:[NSNull null]] )
return @"";
NSString *myString = [EnglishNumString stringByReplacingOccurrencesOfString:@"1" withString:@"۱"];
myString = [myString stringByReplacingOccurrencesOfString:@"2" withString:@"۲"];
myString =[myString stringByReplacingOccurrencesOfString:@"3" withString:@"۳"];
myString =[myString stringByReplacingOccurrencesOfString:@"4" withString:@"۴"];
myString =[myString stringByReplacingOccurrencesOfString:@"5" withString:@"۵"];
myString =[myString stringByReplacingOccurrencesOfString:@"6" withString:@"۶"];
myString =[myString stringByReplacingOccurrencesOfString:@"7" withString:@"۷"];
myString =[myString stringByReplacingOccurrencesOfString:@"8" withString:@"۸"];
myString =[myString stringByReplacingOccurrencesOfString:@"9" withString:@"۹"];
myString =[myString stringByReplacingOccurrencesOfString:@"0" withString:@"۰"];
return myString;
}
答案 7 :(得分:0)
/ ** *在此功能中,将阿拉伯数字转换为英文数字。 * @sample stringValue:传递字符串值。 * /
fun numberArabicToEnglish(stringValue: String): String {
val value = stringValue
.replace("١", "1")
.replace("٢", "2")
.replace("٣", "3")
.replace("٤", "4")
.replace("٥", "5")
.replace("٦", "6")
.replace("٧", "7")
.replace("٨", "8")
.replace("٩", "9")
.replace("٠", "0")
return value
}`enter code here`
答案 8 :(得分:0)
将数字转换为任何语言环境
let formatter = NumberFormatter()
formatter.locale = Locale(identifier: "ar")
if let localized = formatter.string(from: NSNumber(value: comp.0)) {
return "\(localized)"
}
示例:
(lldb)po formatter.string(来自:NSNumber(值:0))▿ 可选的 -有些:“ ٠”
(lldb)po formatter.string(来自:NSNumber(值:1))▿ 可选的 -有些:“ ١”
(lldb)po formatter.string(来自:NSNumber(值:2))▿ 可选的 -有些:“ ٢”
(lldb)po formatter.string(来自:NSNumber(值:3))▿ 可选的 -有些:“ ٣”
(lldb)po formatter.string(来自:NSNumber(值:4))▿ 可选的 -有些:“ ٤”
(lldb)po formatter.string(来自:NSNumber(值:5))▿ 可选的 -有些:“ ٥”
(lldb)po formatter.string(来自:NSNumber(值:6))▿ 可选的 -有些:“ ٦”
(lldb)po formatter.string(来自:NSNumber(值:7))▿ 可选的 -有些:“ ٧”
(lldb)po formatter.string(来自:NSNumber(值:8))▿ 可选的 -有些:“ ٨”
(lldb)po formatter.string(来自:NSNumber(值:9))▿ 可选的 -有些:“ ٩”
(lldb)po formatter.string(来自:NSNumber(值:10))▿ 可选的 -有些:“ ١٠”
答案 9 :(得分:0)
Swift 5和更高版本
如果要创建UILabel的子类:
class LocalizedNumbersLabel: UILabel {
override var text: String? {
didSet {
if let text = text {
let numbersDictionary : Dictionary = ["0" : "۰","1" : "۱", "2" : "۲", "3" : "۳", "4" : "۴", "5" : "۵", "6" : "۶", "7" : "۷", "8" : "۸", "9" : "۹", "." : ","]
var str = text
for (key,value) in numbersDictionary {
str = str.replacingOccurrences(of: key, with: value)
}
if(str != self.text){
self.text = str
}
} else {
}
}
}
}