我是一个关于创建两个类(Tree类和Node类)的大学项目,用Java实现k-ary树。
在类Tree中,应该有一个构造函数,它将int作为输入,表示树形。
我之前曾使用普通树木,这是我的结果:
类树:*
班级节点:*
我绝对不知道在哪里以及如何开始构建这个项目(因为我不知道如何管理arity,也许是使用ArrayList?)。
任何意见和建议将不胜感激:) 提前谢谢。
答案 0 :(得分:3)
以下是类的新版本,以及您需要的方法。
<强>节点强>
import java.util.ArrayList;
import java.util.List;
public class Node {
public Node parent; // The parent of the current node
public List<Node> children; // The children of the current node
public Object info;
public static int maxNrOfChildren; // Equal to the k-arity;
public Node (Object info)
{
this.info=info;
children = new ArrayList<Node>(maxNrOfChildren);
}
public void addChild(Node childNode, int position)
// You must take care so that future insertions don't override a child on i-th position
{
if(position>=maxNrOfChildren-1)
{
// Throw some error
}
else
{
System.out.println("this.children="+this.children);
if(this.children.get(position)!=null)
{
// There is alerady a child node on this position; throw some error;
}
else
{
childNode.parent=this;
this.children.set(position, childNode);
}
}
}
}
<强>树强>
import java.util.ArrayList;
import java.util.List;
public class Tree {
public Node root;
public Tree(int kArity)
{
Node.maxNrOfChildren=kArity;
}
public void addRoot(Object info)
{
root=new Node(info);
root.parent=null;
root.children=new ArrayList<Node>(Node.maxNrOfChildren);
}
public void addNewNodeVasithChildOfNodeU(Node u, Object info, int i)
{
Node child=new Node(info);
u.addChild(child, i);
}
// I've made the above two methods of type void, not Node, because
// I see no reason in returning anything; however, you can override by calling
//'return root;' or 'return child;'
public int numberOfNodesInTree(Node rootNode){
int count=0;
count++;
if(rootNode.children.size()!=0) {
for(Node ch : rootNode.children)
count=count+numberOfNodesInTree(ch);
}
return count;
}
public int numberOfNodesInTree()
{
return numberOfNodesInTree(this.root);
}
public void changeRoot(Node newRoot, int i)
{
Node oldRoot=this.root;
newRoot.parent=null;
newRoot.addChild(oldRoot, i);
oldRoot.parent=newRoot;
this.root=newRoot;
}
public static void main(String args[])
{
Tree tree=new Tree(3);
Node a = new Node("a");
Node b = new Node("b");
Node c = new Node("c");
tree.addRoot("root");
tree.root.addChild(a,0);
a.addChild(b,0);
tree.root.addChild(c,1);
System.out.println(tree.numberOfNodesInTree(tree.root));
}
}
逻辑是正确的,但是当我运行main方法并且我还没有弄清楚问题是什么时,我得到了一些与Java相关的错误。
答案 1 :(得分:1)
这可以作为一个起点:
import java.util.ArrayList;
import java.util.List;
public class Node {
public Node parent;//the parent of the current node
public List<Node> children = new ArrayList<Node>();//the children of the current node
public String name;//or any other property that the node should contain, like 'info'
public static int maxNrOfChildren;//equal to the k-arity;
public Node (String nodeName)
{
name=nodeName;
}
public void addChild(Node childNode)
{
if(this.children.size()>=maxNrOfChildren)
{
//do nothing (just don't add another node), or throw an error
}
else
{
childNode.parent=this;
this.children.add(childNode);
}
}
}
import java.util.ArrayList; import java.util.List;
public class Tree {
public Node root = new Node("root");
public Tree(int kArity)
{
Node.maxNrOfChildren=kArity;
root.parent=null;
}
public void traverseTree(Node rootNode)//depth first
{
System.out.println(rootNode.name);
if(rootNode.children.size()!=0)
for(Node ch : rootNode.children)
traverseTree(ch);
}
public static void main(String args[])
{
Tree tree=new Tree(3);
Node a = new Node("a");
Node b = new Node("b");
Node c = new Node("c");
tree.root.addChild(a);
a.addChild(b);
tree.root.addChild(c);
tree.traverseTree(tree.root);
}
}
请提供有关项目规范的更多详细信息,否则我无法确定您在这些课程中需要哪种功能
答案 2 :(得分:0)
创建k阵列背后的想法是,这不是像列表或集合这样的传统结构,节点就像链表中的元素,它指向另一个子节点,也可以指向对于父母,whant确定该结构中的孩子或父母应该是一个完全不同的问题。至于节点中的子列表,您可以使用任何您想要的结构,ArrayList最有可能是合适的。结构的选择取决于许多因素,如大小,访问的频率,是否需要进行排序等。
答案 3 :(得分:0)
看看这个。希望能帮助到你。
import java.util.ArrayList;
public class Nary
{
public static Node root;
public static int insert(Node rootNode, int parentId, ArrayList<Node> nodeToAdd)
{
if(rootNode == null)
return 0;
if(rootNode.children == null)
rootNode.children = new ArrayList<Node>();
if(rootNode.id == parentId)
{
for(int i =0; i < nodeToAdd.size(); i++)
{
Node node = nodeToAdd.get(i);
node.parent = rootNode;
rootNode.children.add(node);
}
return 1;
}
else
{
for(int i = 0; i < rootNode.children.size(); i++)
{
int resultFlag = insert(rootNode.children.get(i), parentId, nodeToAdd);
if(resultFlag == 1)
{
return 1;
}
}
}
return -1;
}
public static void traverse(Node root)
{
if(root == null)
{
return;
}
System.out.println(root.data + " " + root.id );
for(Node child : root.children)
{
traverse(child);
}
}
public static void main(String[] args) {
// Insertion
root = new Node(0, "root");
int parentId = root.id;
Node Bread = new Node(1, "Bread");
Node Milk = new Node(2, "Milk");
Node Meat = new Node(3, "Meat");
Node Eggs = new Node(4, "Eggs");
ArrayList<Node> nodeList = new ArrayList<Node>();
nodeList.add(Bread);
nodeList.add(Milk);
nodeList.add(Meat);
nodeList.add(Eggs);
insert(root, parentId, nodeList);
// Add children for Bread
parentId = Bread.id;
Node Bread0 = new Node(11, "Whole-Wheat");
Node Bread1 = new Node(12, "Whole-Grain");
Node Bread2 = new Node(13, "Italian");
ArrayList<Node> nodeList1 = new ArrayList<Node>();
nodeList1.add(Bread0);
nodeList1.add(Bread1);
nodeList1.add(Bread2);
insert(root, parentId, nodeList1);
Add children for Milk
parentId = Milk.id;
Node Milk0 = new Node(21, "Whole");
Node Milk1 = new Node(22, "skim");
Node Milk2 = new Node(23, "Almond");
ArrayList<Node> nodeList2 = new ArrayList<Node>();
nodeList2.add(Milk0);
nodeList2.add(Milk1);
nodeList2.add(Milk2);
insert(root, parentId, nodeList2);
traverse(root);
}
}
class Node{
int id;
String data;
Node parent;
ArrayList<Node> children;
public Node(int id, String data)
{
this.id = id;
this.data = data;
}
}