Question

我正在尝试编写一个覆盖二进制文件的函数。现在我编写了这个覆盖文本文件的函数，它完全正常工作：

void myCopy(char source_file[50], char dest_file[50])
{
    FILE *fp1, *fp2;
    char a;
    fp1 = fopen(source_file, "rt");
    if (fp1 == NULL)
    {
        printf("Can't open this file, either it doesn't exist or doesn't contain anything.\n");
    }
    fp2 = fopen(dest_file, "wt");
    if (fp2 == NULL)
    {
        printf("Can't open this file, either it doesn't exist or doesn't contain anything.\n");
    }
    while ((a = fgetc(fp1)) != EOF)//While a failure did not accure.
    {
        fputc(a, fp2);
    }
    fclose(fp1);
    fclose(fp2);
}

我的问题是，有没有办法在不使用fputc，fgetc，fscanf和fprintf的情况下对所有二进制文件执行相同的操作？

Answer 1

如果你删除了“二进制文件”，你的代码将是正确的。来自fopen选项字符串的字符。但是您可以使用fread / fwrite函数和缓冲区来提高复制速度。例如：

const size_t buffer_size = 8192;
char buffer[buffer_size];
while (true) {
    size_t read = fread(buffer, sizeof(char), buffer_size, fp1);

    if (read > 0)
        fwrite(buffer, sizeof(char), buffer_size, fp2);
    else
        break;
}

使用fseek，fread和fwrite处理二进制文件

1 个答案: