Question

每当我尝试通过std :: vector进行交互时，它会一直告诉我：矢量迭代器不兼容

这是让我崩溃的功能：

// These 2 typedefs are declared in structs.h
typedef std::pair<uint32_t, Object*> PlayerContainerPair;
typedef std::vector<PlayerContainerPair> PlayerContainers;

// This is a variable from Player class in player.h
PlayerContainers m_containers;

// Definition of the function found in player.cpp
int32_t Player::GetContainerId(Object* container)
{
    for (PlayerContainers::const_iterator cl = m_containers.begin(); cl != m_containers.end(); ++cl){
        if (cl->second == container)
            return static_cast<int32_t>(cl->first);
    }

    return -1;
}

基本上每当我尝试循环遍历向量时，它都会使我的应用程序崩溃，我检查了对象并且它是一个对象类，它不是空的。

还有什么导致此错误？

Answer 1

使用

for (auto cl = m_containers.begin(); cl != m_containers.end(); ++cl){
    if (cl->second == container)
        return static_cast<int32_t>(cl->first);
}

应解决您的问题

EDIT删除了＆amp;如下所示

最小的例子

#include <iostream>
#include <string>
#include <tuple>
#include <cstdint>
#include <vector>

struct Object {};

// These 2 typedefs are declared in structs.h
typedef std::pair<uint32_t, Object*> PlayerContainerPair;
typedef std::vector<PlayerContainerPair> PlayerContainers;

// This is a variable from Player class in player.h
PlayerContainers m_containers;

// Definition of the function found in player.cpp
int32_t GetContainerId(Object* container)
{

    for (auto cl = m_containers.begin(); cl != m_containers.end(); ++cl){
        if (cl->second == container)
            return static_cast<int32_t>(cl->first);
    }

    return -1;
}

int main()
{
    Object* o = new Object;
    m_containers.push_back(PlayerContainerPair(1, o));
    std::cout << GetContainerId(o);
    return 0;
}

使用vs2013编译并按预期运行

C ++卡通与矢量迭代器不兼容，无法找到原因

1 个答案: