Question

我使用以下代码向boilerpipe java web api发送get请求以将html内容提取到网站的纯文本中，我使用telerivet webhook api向我的php文件所在的服务器发送和接收消息，提供的超时是10秒，我总是使用此代码超时，请帮助我

if ($_POST['secret'] !== $webhook_secret)
{
    header('HTTP/1.1 403 Forbidden');
    echo "Invalid webhook secret";
}
else 
{
    if ($_POST['event'] == 'incoming_message')
    {
        $content = $_POST['content'];
        $from_number = $_POST['from_number'];
        $phone_id = $_POST['phone_id'];

        // do something with the message, e.g. send an autoreply            
        header("Content-Type: application/json");

        $ch = curl_init();
        curl_setopt($ch, CURLOPT_RETURNTRANSFER, true);
        curl_setopt($ch, CURLOPT_URL, 
        'http://boilerpipe-web.appspot.com/extract?url=http://www.kvgengg.com&extractor=DefaultExtractor&output=text&extractImages='
        ));
        $content = curl_exec($ch);
        echo $content;

    }
}

Answer 1

似乎存在语法错误，因为您在网址中有一个额外的括号，我已将其删除。

如果您使用http_build_query传递参数，那么它应该可以解决您的问题

if ($_POST['secret'] !== $webhook_secret)
{
    header('HTTP/1.1 403 Forbidden');
    echo "Invalid webhook secret";
}
else 
{
    if ($_POST['event'] == 'incoming_message')
    {
        $content = $_POST['content'];
        $from_number = $_POST['from_number'];
        $phone_id = $_POST['phone_id'];

        // do something with the message, e.g. send an autoreply            
        header("Content-Type: application/json");

        $ch = curl_init();
        curl_setopt($ch, CURLOPT_RETURNTRANSFER, true);
        curl_setopt($ch, CURLOPT_URL, 
            'http://boilerpipe-web.appspot.com/extract?' . 
            http_build_query(array(
                'url' => 'http://www.kvgengg.com',
                'extractor' => 'DefaultExtractor'
                'output' => 'text',
                'extractImages' => ''
            ))
        );
        $content = curl_exec($ch);
        echo $content;

    }
}

使用PHP发送HTTP GET请求

1 个答案: