我正在寻找一种方法,使用本机PHP获取我的脚本收到的原始HTTP请求,包括标题和正文。阅读PHP文档我无法找到获取原始请求的标准方法,无论使用何种HTTP方法。
例如,当请求页面test.php时,我想获得完整的请求,如:
GET /test.php HTTP/1.1
Host:....
....
....
在POST,HEAD等情况下也一样......
似乎很奇怪,没有一种方法可以访问原始请求缓冲区!
答案 0 :(得分:11)
查看手册似乎没有对请求进行未解析的原始访问以匹配您想要的内容,因此我怀疑您需要从$_SERVER
变量重新构建您想要的内容。快速搜索我发现这个课程,做了一些小改动以获得GET / HTTP/1.1
,也许你会发现它适合你的需要。
<?php
/**
* Access the HTTP Request
*
* Found on http://www.daniweb.com/web-development/php/code/216846/get-http-request-headers-and-body
*/
class http_request {
/** additional HTTP headers not prefixed with HTTP_ in $_SERVER superglobal */
public $add_headers = array('CONTENT_TYPE', 'CONTENT_LENGTH');
/**
* Construtor
* Retrieve HTTP Body
* @param Array Additional Headers to retrieve
*/
function http_request($add_headers = false) {
$this->retrieve_headers($add_headers);
$this->body = @file_get_contents('php://input');
}
/**
* Retrieve the HTTP request headers from the $_SERVER superglobal
* @param Array Additional Headers to retrieve
*/
function retrieve_headers($add_headers = false) {
if ($add_headers) {
$this->add_headers = array_merge($this->add_headers, $add_headers);
}
if (isset($_SERVER['HTTP_METHOD'])) {
$this->method = $_SERVER['HTTP_METHOD'];
unset($_SERVER['HTTP_METHOD']);
} else {
$this->method = isset($_SERVER['REQUEST_METHOD']) ? $_SERVER['REQUEST_METHOD'] : false;
}
$this->protocol = isset($_SERVER['SERVER_PROTOCOL']) ? $_SERVER['SERVER_PROTOCOL'] : false;
$this->request_method = isset($_SERVER['REQUEST_METHOD']) ? $_SERVER['REQUEST_METHOD'] : false;
$this->headers = array();
foreach($_SERVER as $i=>$val) {
if (strpos($i, 'HTTP_') === 0 || in_array($i, $this->add_headers)) {
$name = str_replace(array('HTTP_', '_'), array('', '-'), $i);
$this->headers[$name] = $val;
}
}
}
/**
* Retrieve HTTP Method
*/
function method() {
return $this->method;
}
/**
* Retrieve HTTP Body
*/
function body() {
return $this->body;
}
/**
* Retrieve an HTTP Header
* @param string Case-Insensitive HTTP Header Name (eg: "User-Agent")
*/
function header($name) {
$name = strtoupper($name);
return isset($this->headers[$name]) ? $this->headers[$name] : false;
}
/**
* Retrieve all HTTP Headers
* @return array HTTP Headers
*/
function headers() {
return $this->headers;
}
/**
* Return Raw HTTP Request (note: This is incomplete)
* @param bool ReBuild the Raw HTTP Request
*/
function raw($refresh = false) {
if (isset($this->raw) && !$refresh) {
return $this->raw; // return cached
}
$headers = $this->headers();
$this->raw = "{$this->method} {$_SERVER['REQUEST_URI']} {$this->protocol}\r\n";
foreach($headers as $i=>$header) {
$this->raw .= "$i: $header\r\n";
}
$this->raw .= "\r\n{$this->body}";
return $this->raw;
}
}
/**
* Example Usage
* Echos the HTTP Request back to the client/browser
*/
$http_request = new http_request();
$resp = $http_request->raw();
echo nl2br($resp);
/* Result (less <br> tags)
GET / HTTP/1.1
HOST: localhost:8080
USER-AGENT: Mozilla/5.0 ...
ACCEPT: text/html,application/xhtml+xml,application/xml;...
ACCEPT-LANGUAGE: en-US,en;q=0.5
ACCEPT-ENCODING: gzip, deflate
DNT: 1
COOKIE: PHPSESSID=...
CONNECTION: keep-alive
*/
?>
P.S:不要忘记htmlentities()他们在输出上的值:)
答案 1 :(得分:6)
原始请求不可用于PHP,因为PHP启动时已经消耗了请求。
例如,当PHP作为Apache模块(mod_php
)运行时,Apache会接收并解析请求,并且仅在Apache解析该请求并确定它引用文件后才调用PHP哪个应该由PHP处理。如果PHP作为CGI或FastCGI处理程序运行,它根本不会收到HTTP请求 - 它只会看到请求的CGI格式,这是完全不同的。
答案 2 :(得分:0)
如果你在Apache机器上试试这个:
function get_raw_http_request() {
$request = "{$_SERVER['REQUEST_METHOD']} {$_SERVER['REQUEST_URI']} {$_SERVER['SERVER_PROTOCOL']}\r\n";
foreach (getallheaders() as $name => $value) {
$request .= "$name: $value\r\n";
}
$request .= "\r\n" . file_get_contents('php://input');
return $request;
}