Question

我试图让用户输入元素arrA和arrB应该具有的数量，并且还让用户为两者中的每个对应元素选择他们想要的int号，{{1} }和arrA。然后，使用arrB和arrC中相应元素的总和创建第三个arrA，然后打印arrB，arrA和arrB。

输出应如下所示：

arrC

这是我到目前为止编写的代码，我需要帮助我如何使用扫描程序让用户选择Input the length: 5 Enter a value for first array, position 0: 1 Enter a value for first array, position 1: 6 Enter a value for first array, position 2: 13 Enter a value for first array, position 3: -3 Enter a value for first array, position 4: 8 Enter a value for second array, position 0: 9 Enter a value for second array, position 1: -4 Enter a value for second array, position 2: 1 Enter a value for second array, position 3: 65 Enter a value for second array, position 4: 18 first: 1 6 13 -3 8 second: 9 -4 1 65 18 result: 10 2 14 62 26和arrA的输入长度以及{{1}中的元素}和arrB。这就是代码到目前为止的样子： -

arrA

Answer 1

假设您只有2个数组可以轻松实现并且不嵌套循环，当您理解这些代码时，您可以使用新循环包装所有方法并创建无限数组，以便根据需要求和。 ..但你必须先了解基础知识：

创建扫描程序并询问用户数组的长度：

Scanner sc = new Scanner(System.in);
// ask user!
System.out.println("Input the length:");
int arrayLength = in.nextInt();

使用给定的长度

创建数组

int[] fistArray = new int[arrayLength];
int[] secondArray = new int[arrayLength];
int[] totals = new int[arrayLength];

填充用户输入的从0到数字的第一个数组迭代位置：

for (int i = 0; i < arrayLength; i ++) {
    System.out.println("Enter a value for first array, position "+ i);
    try {
        firstArray[i] = Integer.parseInt(sc.nextLine());
    } catch (Exception e) {
        System.out.println("Not a valid number!!!);
        i --;
    }
}

填充第二个数组迭代位置，从0到用户输入的数字，得到每个pos的总和：

for (int i = 0; i < in.nextInt(); i ++) {
    System.out.println("Enter a value for second array, position "+ i);
    try {
        secondArray[i] = Integer.parseInt(sc.nextLine());
        totals[i] = fistArray[i] + secondArray[i];
    } catch (Exception e) {
        System.out.println("Not a valid number!!!);
        i --;
    }
}

打印结果：

System.out.println(Arrays.toString(firstArray));          
System.out.println(Arrays.toString(secondArray));       
System.out.println(Arrays.toString(totalsArray));

最后，不要忘记关闭扫描仪以避免内存泄漏，如drgPP所示：

sc.close();

Answer 2

以下代码应该按您的要求执行：

import java.util.*;

class ArrayArithmetic
{
   public static void main ( String[] args )
   {
      Scanner in = new Scanner(System.in);
      System.out.print("Input the length ");
      int len = in.nextInt();

      int[] arrA   = new int[len];
      int[] arrB   = new int[len];
      int[] sum    = new int[len];
      for (int i = 0; i < len; i++){
        System.out.print("Enter a value for first array, position " + i + ": ");
        arrA[i] = in.nextInt();
    }
    for (int i = 0; i < len; i++){
        System.out.print("Enter a value for second array, position " + i + ": ");
        arrB[i] = in.nextInt();
    }

    for(int i = 0; i < arrA.length; i++)
    {
     for(int j = 0; i < arrB.length; i++)
     {
       sum[i] = arrA[i] + arrB[i];

   }


}

System.out.println("sum: " + sum[0]+"," + sum[1] + ","  + sum[2] + ","  + sum[3] );


} }

Answer 3

public static void main (String[] args){
            Scanner sc = new Scanner(System.in);
            System.out.println("Length of arrays: ");
            try {
                //Initializing length of array
                int length = sc.nextInt();
                //Constructing our arrays based on length
                int[] arrA = new int[length];
                int[] arrB = new int[length];
                int[] arrSum = new int[length];

                //Populating our array A via a loop
                for (int i=0; i<arrA.length; i++) {
                    System.out.println("Values for arrA at index: "+i);
                    int value = sc.nextInt();
                    arrA[i]=value;
                }
                //Populating our array B via a loop
                for (int i=0; i<arrB.length; i++) {
                    System.out.println("Values for arrB at index: "+i);
                    int value = sc.nextInt();
                    arrB[i]=value;
                }
                //Call the method to calcualte our sum which will be in sum array
                arrSum = makeSum(arrA, arrB, length);

                System.out.println(Arrays.toString(arrSum));
                } catch (Exception e) {
                    e.printStackTrace();
                } finally {
                    sc.close();
                }

    }

    // Method to calculate our Sum Array based on the length and the Array A and B
    public static int[] makeSum (int[] arrA, int[] arrB, int length) {
        int[] arrSum = new int[length];
        for (int i=0; i<arrA.length; i++) {
            for (int j=0; j<arrB.length; j++) {
                arrSum[j]=arrA[i]+arrB[j];
            }
        }
        return arrSum;
    }

Answer 4

也许这是你的问题：

Scanner scan = new Scanner(System.in);

System.out.println("Enter size: ");
int size =scan.nextInt();

Integer[] arrA =  new Integer[size];
ArrayList<Integer> arrB = new ArrayList<Integer>(size);

将两个数组的相应元素添加到第三个数组

4 个答案: