Question

我有两个阵列一个

Array
(
    [0] => Array
        (
            [a] => 30
            [b] => 5
        )

    [1] => Array
        (
            [a] => 30
            [b] => 5
        )

    [2] => Array
        (
            [a] => 30
            [b] => 0
        )

    [3] => Array
        (
            [a] => 5
            [b] => 5
        )

    [4] => Array
        (
            [b] => 15
            [a] => 0
        )

)

第二个数组

Array
(
    [0] => Array
        (
            [a] => 207
            [b] => 225
        )

    [1] => Array
        (
            [b] => 35
            [a] => 0
        )

    [2] => Array
        (
            [a] => 35
            [b] => 90
        )

    [3] => Array
        (
            [a] => 80
            [b] => 140
        )

    [4] => Array
        (
            [a] => 40
            [b] => 35
        )
)

我想在相同的键上添加这两个数组，某些位置的键的顺序是不同的[a]和[b]

提前致谢

Answer 1

假设这些数组具有相同的结构，这有望为您提供总数的第三个数组：

$array3 = Array();
reset($array1);
while (list($key) = each($array1)) {
    reset($array1[$key]);
    while (list($k,$v) = each($array1[$key])) {
        $array3[$key][$k] = $v + $array2[$key][$k];
    }
}

Answer 2

这假设两个数组的长度始终相同，并且子数组始终只包含a和b索引。

$result = array();

foreach($arrayOne as $key => $value)
{
    $result[] = array(
        "a" => $value["a"] + $arrayTwo[$key]["a"],
        "b" => $value["b"] + $arrayTwo[$key]["b"]
    );
}

DEMO

Answer 3

我认为这是for循环和数组的课堂作业。

$array1 = array(....);
$array2 = array(....);
$finalArray = array();

$count = count($array1);
for (i = 0; $i < $count; $i++) {
    $totalArray[a] = $array1[i][a] + $array2[i][a];
    $totalArray[b] = $array1[i][b] + $array2[i][b];
    $finalArray[] = $totalArray;
}

添加两个数组元素

3 个答案: