在Processing中移动透视消失点

Question

我的应用程序有一个分屏模式，其中只有一半的屏幕用于显示3D场景。所以我希望消失点放在左半部分的中间。

我已尝试camera()和translate()的各种组合，但消失点不会从草图窗口的中心移动一个像素。

 

void setup(){
  size(800,400, P3D);
  fill(255,120);
}

void draw(){

  background(111);

  float camEyeX = 0;
  float camEyeY = 400;
  float camEyeZ = (height/2) / tan(PI/6);
  float camCenterX = 0;
  float camCenterY = -200;
  float camCenterZ = 0;
  float camUpX = 0;
  float camUpY = 1;
  float camUpZ = 0;

  pushMatrix();
  camera( camEyeX, camEyeY, camEyeZ, camCenterX, camCenterY, camCenterZ, camUpX, camUpY, camUpZ );
  translate( -200, 0, 0);
  rectMode(CENTER);
  rect(0,0, 800,400);
  rect(0,0, 100,100);
  popMatrix();
  hint(DISABLE_DEPTH_TEST);
  rectMode(CORNER);
  rect(400,0, 400,400);
  hint(ENABLE_DEPTH_TEST);
}

关于这个话题，我刚刚发现this unanswered question十年前曾问过...... 有谁知道这是否有可能实现？

Answer 1

您可以使用PGraphics leftSide; void setup(){ size(800,400, P3D); leftSide = createGraphics(width/2, height, P3D); } void draw(){ leftSide.beginDraw(); leftSide.background(111); float camEyeX = 0; float camEyeY = 400; float camEyeZ = (height/2) / tan(PI/6); float camCenterX = 0; float camCenterY = -200; float camCenterZ = 0; float camUpX = 0; float camUpY = 1; float camUpZ = 0; leftSide.pushMatrix(); leftSide.camera( camEyeX, camEyeY, camEyeZ, camCenterX, camCenterY, camCenterZ, camUpX, camUpY, camUpZ ); leftSide.translate( -200, 0, 0); leftSide.rectMode(CENTER); leftSide.rect(0,0, 800,400); leftSide.rect(0,0, 100,100); leftSide.popMatrix(); leftSide.hint(DISABLE_DEPTH_TEST); leftSide.rectMode(CORNER); leftSide.rect(400,0, 400,400); leftSide.hint(ENABLE_DEPTH_TEST); leftSide.endDraw(); image(leftSide, 0, 0); } 函数为左视口创建缓冲区，然后绘制到缓冲区，然后将缓冲区绘制到屏幕上。

 

find

可以在the reference找到更多信息。