Question

我有以下段落：

This is the first line.
this is the second line.
we live in Europe.
this is the fourth line.

我想在每个换行符中将第一个字符转换为uppercase。

因此段落应如下所示：

This is the first line.
This is the second line.
We live in Europe.
This is the fourth line.

到目前为止，我可以将第一个字符转换为大写字母，但它会使用ucfirst()和ucword()

转换每个字中不是换行符中的第一个字符

echo ucfirst($str);

有没有办法使用ucfirst()或preg_replace()函数来解决这个问题？

谢谢！

Answer 1

这个怎么样？

$a = "This is the first line.\n\r
this is the second line.\n\r
we live in Europe.\n\r
this is the fourth line.";

$a = implode("\n", array_map("ucfirst", explode("\n", $a)));

Answer 2

你可以使用它。

<?php
$str = strtolower('This is the first line.
This is the second line.
We live in Europe.
This is the fourth line.');
$str = preg_replace_callback('~^\s*([a-z])~im', function($matches) { return strtoupper($matches[1]); }, $str);
echo $str;

输出：

This is the first line.
This is the second line.
We live in europe.
This is the fourth line.

i修饰符表示我们不关心这种情况，m表示字符串的每一行都是^的新行。这将大写一行的第一个字母，假设它以a-z开头。

Answer 3

另一种方法是：

    <?php

   function foo($paragraph){

        $parts = explode("\n", $paragraph);
        foreach ($parts as $key => $line) {  
            $line[0] = strtoupper($line[0]);
            $parts[$key] = $line;
        }

        return implode("\n", $parts);
    }

    $paragraph = "This is the first line.
    this is the second line.
    we live in Europe.
    this is the fourth line.";

    echo foo($paragraph);
?>

Answer 4

用大写字母替换每行的第一个下套管字符：

$str = preg_replace_callback(
            '/^\s*([a-z])/m',
            function($match) {
                return strtoupper($match[1]);
            },
            $str);

在php中的每个换行符中将第一个字符转换为大写

4 个答案: