Question

我正在制作一个玩Go Fish游戏的程序。循环一次后，除scan.next()之外的所有内容都有效。

嗯，有时它会起作用，有时则不起作用。这是代码：

System.out.println(compHand.showHand());       

while (!(deck.isEmpty())) {
    y = 0;

    while (x == 1) {             

        System.out.println("\nYour hand:" + userHand.showHand()+ "\nYour turn. What number do you want to match?");
        guess = scan.next();
        if (compHand.checkHand(guess)) {
            System.out.println("Darn...here you go.");
            userHand.removeNum(guess);
            compHand.removeNum(guess);
            userHand.showHand();
            uP++;
        }
        else {
            System.out.println("Nope! Type '1' to go fish!");
            y = scan.nextInt();
            if (y == 1) {
                userHand.goFish();
                System.out.println(userHand.showHand()); 
            }
            y = 0;
        }

        guess = "";
        x--;
    }

    while (x == 0) {
        System.out.println("Do you have any " + compHand.ask() + "s?");
        ans = scan.next();
            if (!(ans.contains("go"))) {
                System.out.println("Yay!");
                userHand.removeNum(ans);
                compHand.removeNum(ans);
                cP++;
                x++;
            }
            else {
                System.out.println("Aww...darn.");
                compHand.goFish();
                x++;
            }
        }

        System.out.println("Computer's points so far: " + cP + "\nYour points so far: " + uP + "\n");
    }        
}

所以它第一次循环来做用户的手，它的工作原理。然后它适用于计算机，但如果计算机必须去钓鱼。当它循环回到用户手上时，它会跳过guess = scan.next();。我不知道该怎么做......

Answer 1

问题来自缓冲区。你必须免费它。为此，将一个scan.nextLine（）放在循环的右括号之前，它将释放缓冲区。然后，您就可以输入输入。

scan.next（）在循环中不起作用

1 个答案: