Question

我希望将矩阵乘以大值
这是我的代码

import time
import numpy


def mm( mtx_a, mtx_b):
tpos_b = zip( *mtx_b)
rtn = [[ sum( ea*eb for ea,eb in zip(a,b)) for b in tpos_b] for a in mtx_a]
return rtn

print ("first part of project of OS")
N=input("select the size of N*N matrix by entering the power of 10 \n")

N=10**N
startTime = time.time()

try:
    P=numpy.random.randint(-100,100,size=(N,N))
    Q=numpy.random.randint(-100,100,size=(N,N))

C=mm(P,Q)
except MemoryError:
     print("Memory error")


try:
     A=numpy.random.randint(-1000,1000,size=(N,N))
     B=numpy.random.randint(-5000,5000,size=(N,N))
except MemoryError:
      print("Memory error")


try:

    D=mm(A,B)
    D=mm (D,C)
    print D
except NameError:
     print("name error")


elapsedTime = time.time() - startTime
     print elapsedTime

我得到RuntimeWarning：在long_scalars中遇到溢出ERROR有什么办法可以跳过这个错误？它显示的答案是错的吗？

Answer 1

要乘以数组，您只需使用numpy.dot(A,B)

 A=numpy.random.randint(-1000,1000,size=(1000,1000))
 B=numpy.random.randint(-5000,5000,size=(1000,1000))
 C=numpy.dot(A,B)

>> array([[ -19276757, -143164893,  -46042782, ...,   54192473,  -11723491,
         -24682938],
       [ -13712042,  -81161007,  -10673794, ...,  -60976103,   12684946,
         -38034048],
       [ -33019063,  -31452735,    6885214, ...,  -11402430,  -67335345,
          28926860],
       ...,
       [ -75416394,  -86704514,   55883100, ...,   -9195721,   14717256,
           1028573],
       [ -73945244,   72442826,  -38529094, ...,   -1450784,   34663409,
         -88472364],
       [ -21366137,   91174501,   32863977, ...,   11465498,   57130349,
          47305071]])

RuntimeWarning：在矩阵乘法中的long_scalars中遇到溢出

1 个答案: