jQuery获取数据属性并滑动它的父级

时间:2015-05-19 01:36:19

标签: javascript jquery html css

我有一些链接(见下文),其中我放置了data-navigation属性,而我正在尝试做的是data-section属性slidesDown基于它的数据导航父级

HTML

<ul class="main-navbar-right">
    <li><a href="#" data-navigation="home">Home</a></li>
    <li><a href="#" data-navigation="explore">Explore</a></li>
    <li><a href="#" data-navigation="news">News</a></li>
</ul>

<section id="-navbar-home" data-section="home">
    <p>Home content</p>
</section>

<section id="-navbar-explore" data-section="explore">
    <p>Home explore</p>
</section>

<section id="-navbar-explore" data-section="news">
    <p>Home news</p>
</section>

CSS

#-navbar-home,
#-navbar-explore,
#-navbar-news {
    display: none;
}

JavaScript / jQuery(我到目前为止,无法继续)

$(document).ready(function() {
    $('li > a').hover(function() {
        var navigation = $("a").data("navigation");
        var section = $("section").data("section");
        $(section).slideDown();
    });
});

JS Fiddle

http://jsfiddle.net/66qz2by8/

1 个答案:

答案 0 :(得分:1)

尝试使用Attribute Equals Selector [name="value"]

var navigation = $(this).data("navigation");
var section = $("section[data-section=" + navigation + "]");
$(section).slideDown();