Question

我有一个用Java脚本编写的轮播我想将其父项create table tab_b(id int, A_id int, `key` varchar(20), `value` varchar(20)); insert into tab_b values (1,1,'text1','test_value1'), (2,1,'text2','test_value2'); create table tab_a(id int,text1 varchar(20),text2 varchar(20)); insert into tab_a(id,text1,text2) select id,max(text1) text1,max(text2) text2 from( select a_id as id, case when `key`='text1' then `value` end text1, case when `key`='text2' then `value` end text2 from tab_b) a; src属性的img标签的<a>属性更改为“ true”。您能帮我吗，我实际上需要将"aria-selected"的名称从img更改为teacher.png，所以我必须使用它的当前名称，并在其中添加teacher-active.png值。

"-active"

// Handle setting the currently active link
pnProductNavContents.addEventListener("click", function(e) {
    var links = [].slice.call(document.querySelectorAll(".pn-ProductNav_Link"));
    links.forEach(function(item) {
        item.setAttribute("aria-selected", "false");
        })
    e.target.setAttribute("aria-selected", "true");
      // Pass the clicked item and it's colour to the move indicator function
    moveIndicator(e.target, colours[links.indexOf(e.target)]);
});

Answer 1

如果我理解正确性，则希望在当前item范围内获取图像元素，并替换其src。所以这样的事情应该起作用：

links.forEach(function(item) {
    item.setAttribute("aria-selected", "false");
    var image = item.querySelector('img');
    var currentSrc = image.getAttribute('src');
    var newSrc = currentSrc.replace('.png', '-active.png');
    image.setAttribute('src', newSrc);
});

如何更改img src属性作为其父选择

1 个答案: