我在屏幕上移动了精灵。现在我抓住了触摸,如果精灵被触摸 - 我将其删除。但我想把它擦掉。含义 - 我在其中滑动(任何方向),如果它是正确的精灵(检查名称) - 将其删除。
我确实有触控密码,但我认为不需要粘贴在这里,它非常标准,滑动代码肯定会有所不同。
有什么建议吗?谢谢!
答案 0 :(得分:4)
试试这个:
override func touchesMoved(touches: Set<NSObject>, withEvent event: UIEvent)
{
let touch = touches.first as! UITouch
let location = touch.locationInNode(self)
if sprite.frame.contains(location)
{
//remove sprite here
}
}
此外,如果您希望在触摸时删除它,也可以添加它:
override func touchesBegan(touches: Set<NSObject>, withEvent event: UIEvent)
{
let touch = touches.first as! UITouch
let location = touch.locationInNode(self)
if sprite.frame.contains(location)
{
//remove sprite here
}
}
答案 1 :(得分:0)
您可以使用UISwipeGestureRecognizer
并获取开始触摸位置。之后,您可以检查该位置的节点。
就像那样:
override func didMoveToView(view: SKView) {
//create Swipe gesturerecognizer
var swipe = UISwipeGestureRecognizer()
//set Direction to Left
swipe.direction = .Left
//Call method "swipe" if swipe is done
swipe.addTarget(self, action: "swipe:")
self.view!.addGestureRecognizer(swipe)
}
func swipe(sender: UISwipeGestureRecognizer){
//get amount of touches in swipe
var touches = sender.numberOfTouches()
//loop through touches
for touch in 0..<touches{
var location = sender.locationOfTouch(touch, inView: self.view)
//Get the node at the location of the touch
var swipedNode = self.nodeAtPoint(location)
}
}