Question

我有一个这样的课程：

class myClass:public QThread

然后在我的构造函数中：

myClass::myClass(){
    moveToThread(this);
    ...
}

似乎所有成员插槽实际上都在工作线程上工作。但是在这种情况下如何在解构过程中阻止线程呢？

Answer 1

根本不做那样的线程。

Qt docs中描述了使用moveToThread()的正确方法：

class Worker : public QObject
{
    Q_OBJECT

public slots:
    void doWork(const QString &parameter) {
        QString result;
        /* ... here is the expensive or blocking operation ... */
        emit resultReady(result);
    }

signals:
    void resultReady(const QString &result);
};

class Controller : public QObject
{
    Q_OBJECT
    QThread workerThread;
public:
    Controller() {
        Worker *worker = new Worker;
        worker->moveToThread(&workerThread);
        connect(&workerThread, &QThread::finished, worker, &QObject::deleteLater);
        connect(this, &Controller::operate, worker, &Worker::doWork);
        connect(worker, &Worker::resultReady, this, &Controller::handleResults);
        workerThread.start();
    }
    ~Controller() {
        workerThread.quit();
        workerThread.wait();
    }
public slots:
    void handleResults(const QString &);
signals:
    void operate(const QString &);
};

或继承QThread，例如：

class WorkerThread : public QThread
{
    Q_OBJECT
    void run() Q_DECL_OVERRIDE {
        QString result;
        /* ... here is the expensive or blocking operation ... */
        emit resultReady(result);
    }
signals:
    void resultReady(const QString &s);
};

void MyObject::startWorkInAThread()
{
    WorkerThread *workerThread = new WorkerThread(this);
    connect(workerThread, &WorkerThread::resultReady, this, &MyObject::handleResults);
    connect(workerThread, &WorkerThread::finished, workerThread, &QObject::deleteLater);
    workerThread->start();
}

但不是两个同时。有关该主题的更多信息here

问：如何正确使用moveToThread（this）？

1 个答案: