Question

我有以下课程：

class commMonitor : QObject
{
    Q_OBJECT
public:
    commMonitor();
    ~commMonitor();
private:
    QMap<unsigned short int, QTimer*> Monitors;
    QTimer* currTimer;
public slots:
    void createMonitor(unsigned short int);
    void deleteMonitor(unsigned short int);
    void startMonitor(unsigned short int);
    void stopMonitor(unsigned short int);

};

当我尝试执行以下操作时：

commMonitor* commOverWatch = new commMonitor();
QThread* monitorThread = new QThread();
commOverWatch->moveToThread(monitorThread);

visual studio将无法编译，错误是QObject :: moveToThread无法访问。

这里出了什么问题？

Answer 1

在C ++中class commMonitor : QObject表示私有继承（默认情况下），因此在您的情况下不能使用公共成员。我希望你熟悉继承规则。如果不是，see this question.正如您所看到的，在您的情况下，moveToThread()是一种私有方法，当然您无法在课堂外访问它。

解决方案：明确指定公共继承：

class commMonitor : public QObject
{
    Q_OBJECT
public:
    commMonitor();
    ~commMonitor();
private:
    QMap<unsigned short int, QTimer*> Monitors;
    QTimer* currTimer;
public slots:
    void createMonitor(unsigned short int);
    void deleteMonitor(unsigned short int);
    void startMonitor(unsigned short int);
    void stopMonitor(unsigned short int);

};

movetothread是可访问的

1 个答案: