Question

我有一张桌子如下。

customer_number      note       loayltystatus    Tier_code
123                  yes
123                  yes        1                 
123                                               1

如何在select语句中组合上面两行中的一行？

EG：

customer_number      note       loayltystatus    Tier_code
    123                  yes    1                1

Answer 1

SELECT customer_number, MAX(note),MAX(loyaltyStatus),MAX(Tier_code)
FROM yourTable
GROUP BY customer_number

Answer 2

我使用SQL Server FOR XML语句将多行组合成一行。这将考虑每个行中具有不同值的任意数量的行。

IF OBJECT_ID(N'tempdb..#t') IS NOT NULL DROP TABLE #t
CREATE TABLE #t
(
    customer_number INT,
    note            NVARCHAR(100),
    loyaltystatus   INT,
    Tier_code       INT
)

INSERT INTO #t SELECT 123, N'yes', NULL, NULL

INSERT INTO #t SELECT 123, N'yes', 1, NULL

INSERT INTO #t SELECT 123, N'yes', NULL, 1

INSERT INTO #t SELECT 123, N'something else', NULL, NULL


SELECT
    customer_number,
        STUFF(
            (SELECT DISTINCT N',' + note
               FROM #t AS s               
               WHERE s.customer_number = t.customer_number
               ORDER BY N',' + note
               FOR XML PATH(''), TYPE).value('.',N'nvarchar(max)')
        ,1,1,N'') AS note,
        STUFF(
            (SELECT DISTINCT N',' + CAST(loyaltystatus AS NVARCHAR(100))
               FROM #t AS s               
               WHERE s.customer_number = t.customer_number
               ORDER BY N',' + CAST(loyaltystatus AS NVARCHAR(100))
               FOR XML PATH(''), TYPE).value('.',N'nvarchar(max)')
        ,1,1,N'') AS loyaltystatus,
        STUFF(
            (SELECT DISTINCT N',' + CAST(Tier_code AS NVARCHAR(100))
               FROM #t AS s               
               WHERE s.customer_number = t.customer_number
               ORDER BY N',' + CAST(Tier_code AS NVARCHAR(100))
               FOR XML PATH(''), TYPE).value('.',N'nvarchar(max)')
        ,1,1,N'') AS Tier_code
FROM
    #t AS t
GROUP BY customer_number

在sql中有两行到一行

2 个答案: