我有一个代码可以访问Twitter提要并将文本放入表格中。然后我编辑了代码,这样我就可以在不同的视图中以自定义的方式显示文本,但我也希望从推文中获取图像,尽管搜索超过一个小时但找不到一个引用。我已经看过如何" Post"图像,但要清楚,我需要得到"显示"来自推文的图片。
以下是处理Twitter Access的代码的重点:
-(void)twitterTimeLine
{
ACAccountStore *account = [[ACAccountStore alloc] init];
ACAccountType *accountType = [account accountTypeWithAccountTypeIdentifier:ACAccountTypeIdentifierTwitter];
[account requestAccessToAccountsWithType:accountType options:nil completion:^(BOOL granted, NSError *error) {
if (granted == YES)
{
NSArray *arrayOfAccounts = [account accountsWithAccountType:accountType];
if ([arrayOfAccounts count] > 0)
{
ACAccount *twitterAccount = [arrayOfAccounts lastObject]; // last account on list of accounts
NSURL *requestAPI = [NSURL URLWithString:@"https://api.twitter.com/1.1/statuses/user_timeline.json"];
NSMutableDictionary *parameters = [[NSMutableDictionary alloc] init];
[parameters setObject:@"30" forKey:@"count"];
[parameters setObject:@"1" forKey:@"incude_entities"];
SLRequest *posts = [SLRequest requestForServiceType:SLServiceTypeTwitter requestMethod:SLRequestMethodGET URL:requestAPI parameters:parameters];
posts.account = twitterAccount;
[posts performRequestWithHandler:^(NSData *response, NSHTTPURLResponse *urlResponse, NSError *error) {
if (response)
{
// TODO: might want to check urlResponse.statusCode to stop early
NSError *jsonError; // use new instance here, you don't want to overwrite the error you got from the SLRequest
NSArray *array =[NSJSONSerialization JSONObjectWithData:response options:NSJSONReadingMutableLeaves error:&jsonError];
if (array) {
if ([array isKindOfClass:[NSArray class]]) {
self.array = array;
NSLog(@"resulted array: %@",self.array);
}
else {
// This should never happen
NSLog(@"Not an array! %@ - %@", NSStringFromClass([array class]), array);
}
}
else {
// TODO: Handle error in release version, don't just dump out this information
NSLog(@"JSON Error %@", jsonError);
NSString *dataString = [[NSString alloc] initWithData:response encoding:NSUTF8StringEncoding];
NSLog(@"Received data: %@", dataString ? dataString : response); // print string representation if response is a string, or print the raw data object
}
}
else {
// TODO: show error information to user if request failed
NSLog(@"request failed %@", error);
}
self.array = [NSJSONSerialization JSONObjectWithData:response options:NSJSONReadingMutableLeaves error:&error];
if (self.array.count != 0)
{
dispatch_async(dispatch_get_main_queue(), ^{
[self.tableView reloadData]; // this part loads into table - important!
});
}
}];
}
}
else
{
NSLog(@"%@", [error localizedDescription]);
}
}];
}
以下是我如何显示推文
-(UITableViewCell *)tableView:(UITableView *)tableView cellForRowAtIndexPath:(NSIndexPath *)indexPath
{
static NSString *cellID = @"cellID";
UITableViewCell *cell = [tableView dequeueReusableCellWithIdentifier:cellID];
if (cell == nil)
{
cell = [[UITableViewCell alloc] initWithStyle:UITableViewCellStyleDefault reuseIdentifier:cellID];
}
NSDictionary *tweet = _array[indexPath.row];
cell.textLabel.text = tweet[@"text"];
//NSString *element = [myArray objectAtIndex:2];
//NSString *element = myArray[2];
// I created some custom views to show the text, but kept the table for testing purposes
TemplateView *tempView = [viewArray objectAtIndex:testCounter];
tempView.TweetView.text = tweet[@"text"];
// -> this was what I was hoping for // tempView.ContentView.image = tweet[@"image"];
testCounter++;
if (testCounter >= 30)
{
testCounter = 0;
}
return cell;
}
我拿出了我认为需要查看的关键线:
tempView.TweetView.text = tweet[@"text"];
tempView.ContentView.image = tweet[@"image"];
//希望后者能像第一个那样起作用,但很明显它并不那么简单
这可能是不可能的,如果是这样的话,我将如何从"链接" (网址)并确保它是图片而不是视频或其他网站?
我可以设置一个"字搜索"从tweet中获取以http开头的文本,并希望从字符串中生成一个URL
答案 0 :(得分:2)
TWTRTweet
对象也没有实体或媒体属性!
不确定任何人都可以开发出如此糟糕的API ..在任何情况下,我都颠倒了内部发出的服务器调用,并发现它发送了其他"未记录的"参数..
示例:
TWTRAPIClient *client = [[TWTRAPIClient alloc] init];
NSString *endpoint = @"https://api.twitter.com/1.1/statuses/user_timeline.json";
NSDictionary *params = @{@"screen_name":@"SCREEN_NAME_HERE",
@"count": @"30"};
即使您有@"include_entities" : @"true"
,也会返回NO MEDIA ..
解决方案:
TWTRAPIClient *client = [[TWTRAPIClient alloc] init];
NSString *endpoint = @"https://api.twitter.com/1.1/statuses/user_timeline.json";
NSDictionary *params = @{@"screen_name":@"SCREEN_NAME_HERE",
@"count": @"30",
@"tweet_mode": @"extended"};
将tweet_mode
设置为extended
(tweet_mode
是一个未记录的参数),它现在将返回媒体作为响应的一部分..这包括"类型&# 34;这是"照片"对于图像。
答案 1 :(得分:0)
我们可以通过将“filter = images”查询应用于“include_entities = true”来获取带有图片的推文。它将向媒体实体发送推文,在其下我们可以看到type =“photo”和其他相关数据。
对于前: https://api.twitter.com/1.1/search/tweets.json?q=nature&include_entities=true&filter=images
在Twitter开发者控制台上尝试此查询,并查看响应格式:https://dev.twitter.com/rest/tools/console
希望这会有所帮助。