Question

我已将我的查询从oracle更改为sql并进行了一些更改，现在我有了最后的sql server查询，但是我收到错误＆＃34;每个GROUP BY表达式必须包含至少一个不是外部引用的列＆＃34;当我运行以下查询。

SELECT
                    startdate AS EnforcementDate,
                    'NULL' AS DistrictNo,
                    CASE
                        WHEN LEN(COALESCE(civicno,0))<=2
                        THEN '0'
                        WHEN LEN(COALESCE(civicno,0))>2
                        THEN ISNULL(SUBSTRING(cast(civicno as VARCHAR(6)),1,LEN(civicno)-2), '')+'00'
                    END                     AS civicno,
                    UPPER(streetname)       AS streetname,
                    COUNT(*)                AS TimingCount,
                    0                       AS ticketcount,
                    0                       AS LPRCount,
                    0                       AS ROSACount,
                    STUFF(( SELECT ','+ AGENTNO FROM platetiming a Where 
                    b.AGENTNO = a.AGENTNO FOR XML PATH('')),1 ,1, '') agentno ,
                    0                                  AS PRVCount,
                    0                            AS OfficersCount 
                FROM
                    platetiming b
                WHERE
                    b.startdate = 2015-01-01 and b.streetname is not null
                GROUP BY
                    b.startdate,
                  'NULL',
                    CASE
                        WHEN LEN(COALESCE(civicno,0))<=2
                        THEN '0'
                        WHEN LEN(COALESCE(civicno,0))>2
                        THEN ISNULL(SUBSTRING(cast(civicno as VARCHAR(6)),1,LEN(civicno)-2), '')+'00'
                    END ,
                    UPPER(streetname)

`

Answer 1

对于GROUP BY，SELECT列表中的每一列都应该在GROUP BY子句中。你错过了很多。此外，使用CTE会更容易，然后您的GROUP BY只需要处理列名，而不是函数。

以下是我将如何编写它的示例，并根据需要进行更改：

with t1 as (
SELECT startdate AS EnforcementDate,
    'NULL' AS DistrictNo,
    CASE
    WHEN LEN(COALESCE(civicno,0))<=2
    THEN '0'
    WHEN LEN(COALESCE(civicno,0))>2
    THEN ISNULL(SUBSTRING(cast(civicno as VARCHAR(6)),1,LEN(civicno)-2), '')+'00'
    END  AS civicno,
    UPPER(streetname) AS streetname,
    COUNT(*) AS TimingCount,
    0 AS ticketcount,
    0 AS LPRCount,
    0 AS ROSACount,
    STUFF(( SELECT ','+ AGENTNO FROM platetiming a Where 
        b.AGENTNO = a.AGENTNO FOR XML PATH('')),1 ,1, '') agentno ,
    0 AS PRVCount,
    0 AS OfficersCount 
    FROM platetiming b
    WHERE b.startdate = 2015-01-01 and b.streetname is not null 
)
select *, count(*) as TimingCount
from t1
GROUP BY
startdate, DistrictNo, civicno, streetname, ticketcount, LPRCount, ROSACount, PRVCount, OfficersCount

GROUP BY表达式必须至少包含一列

1 个答案: