我有一个大型查询实际上是一个视图，它在Oracle中有效，但在MS-SQL Server中没有。 UNION查询的后半部分故意具有硬编码值。
我发布了在Oracle 11g中运行的原始查询，但我尝试了另一种方法，它没有两个硬编码值为0，＆＃39;财务＆＃39;。该尝试发布在底部。
我收到的错误是：每个GROUP BY表达式必须包含至少一个不是外部引用的列。
SELECT
RECOVERYTXNLEDGER.TXN_ID AS TXN_ID,
RECOVERYTXNLEDGER.REC_PROC_ID AS RECORD_PROC_ID,
RECOVERYPROCESS.REC_PROC_NAME AS RECORD_PROC_NAME,
RECOVERYPROCESS.REC_PROC_TYPE_ID AS RECORD_PROC_TYPE_ID,
RECOVERYPROCTYPE.REC_PROC_TYPE_NAME AS RECORD_PROC_TYPE_NAME,
RECOVERYPROCESS.REC_PROC_SEQ AS RECORD_PROC_SEQUENCE_NUM,
RECOVERYTXNLEDGER.SVC_ID AS SERVICE_ID,
SERVICECATALOG.SVC_REF AS SERVICE_REFERENCE,
SERVICECATALOG.SVC_DESC AS SERVICE_DESCRIPTION,
SERVICECATALOG.SDG_ID AS SERVICE_STUDY_GROUP_ID,
STUDYGROUP1.SDG_REF AS SERVICE_STUDY_GROUP_REF,
STUDYGROUP1.SDG_DESC AS SERVICE_STUDY_GROUP_DESC,
RECOVERYTXNLEDGER.SVC_PER_ID AS SERVICE_PERIOD_ID,
PERIOD1.PER_REF AS SERVICE_PERIOD_REFERENCE,
PERIOD1.PER_DESC AS SERVICE_PERIOD_DESCRIPT,
RECOVERYTXNLEDGER.SVC_SCN_ID AS SERVICE_SCENARIO_ID,
SCENARIO1.SCN_DESC AS SERVICE_SCENARIO_DESC,
RECOVERYTXNLEDGER.SVC_RATE AS SERVICE_RATE,
RECOVERYTXNLEDGER.REC_TRANS_TYPE_ID AS TRANS_TYPE_ID,
RECOVERYTRANSTYPE.REC_TRANS_TYPE_NAME AS TRANS_TYPE_NAME,
RECOVERYTXNLEDGER.CUST_ACCT_REF AS CUSToMER_ACCOUNT,
RECOVERYTXNLEDGER.ORG_REF AS ORGANIZATION_REFERENCE,
ORGANIZATION.ORG_DESC AS ORGANIZATION_DESCRIPTION,
STUDYGROUP.SDG_ID AS STUDY_GROUP_ID,
STUDYGROUP.SDG_REF AS STUDY_GROUP_REFERENCE,
STUDYGROUP.SDG_DESC AS STUDY_GROUP_DESCRIPT,
SUM(RECOVERYTXNLEDGER.REC_AMT) AS TRANSACTION_AMOUNT,
RECOVERYTXNLEDGER.VOL_ID AS VOLUME_ID,
VOLUMECATALOG.VOL_REF AS VOLUME_REFERENCE,
VOLUMECATALOG.VOL_DESC AS VOLUME_DESCRIPTION,
RECOVERYTXNLEDGER.VOL_PER_ID AS VOLUME_PERIOD_ID,
PERIOD.PER_REF AS VOLUME_PERIOD_REFERENCE,
PERIOD.PER_DESC AS VOLUME_PERIOD_DESCRIPT,
RECOVERYTXNLEDGER.VOL_SCN_ID AS VOLUME_SCENARIO_ID,
SCENARIO.SCN_DESC AS VOLUME_SCENARIO_DESCRIPT,
RECOVERYTXNLEDGER.VOL_QTY AS VOLUME_QUANTITY
FROM RECOVERYTXNLEDGER
INNER JOIN SCENARIO SCENARIO1 ON RECOVERYTXNLEDGER.SVC_SCN_ID = SCENARIO1.SCN_ID
INNER JOIN SERVICECATALOG ON RECOVERYTXNLEDGER.SVC_ID = SERVICECATALOG.SVC_ID
INNER JOIN STUDYGROUP STUDYGROUP1 ON SERVICECATALOG.SDG_ID = STUDYGROUP1.SDG_ID
INNER JOIN PERIOD PERIOD1 ON RECOVERYTXNLEDGER.SVC_PER_ID = PERIOD1.PER_ID
INNER JOIN RECOVERYPROCESS ON RECOVERYTXNLEDGER.REC_PROC_ID = RECOVERYPROCESS.REC_PROC_ID
INNER JOIN RECOVERYPROCTYPE ON RECOVERYPROCESS.REC_PROC_TYPE_ID = RECOVERYPROCTYPE.REC_PROC_TYPE_ID
INNER JOIN ORGANIZATION ON RECOVERYTXNLEDGER.ORG_REF = ORGANIZATION.ORG_REF
INNER JOIN STUDYGROUP ON ORGANIZATION.SDG_ID = STUDYGROUP.SDG_ID
INNER JOIN RECOVERYTRANSTYPE ON RECOVERYTXNLEDGER.REC_TRANS_TYPE_ID = RECOVERYTRANSTYPE.REC_TRANS_TYPE_ID
INNER JOIN VOLUMECATALOG ON RECOVERYTXNLEDGER.VOL_ID = VOLUMECATALOG.VOL_ID
INNER JOIN PERIOD ON RECOVERYTXNLEDGER.VOL_PER_ID = PERIOD.PER_ID
INNER JOIN SCENARIO ON RECOVERYTXNLEDGER.VOL_SCN_ID = SCENARIO.SCN_ID
GROUP BY
RECOVERYTXNLEDGER.REC_PROC_ID,
RECOVERYTXNLEDGER.TXN_ID,
RECOVERYPROCESS.REC_PROC_NAME,
RECOVERYPROCESS.REC_PROC_TYPE_ID,
RECOVERYPROCTYPE.REC_PROC_TYPE_NAME,
RECOVERYPROCESS.REC_PROC_SEQ,
RECOVERYTXNLEDGER.SVC_ID,
SERVICECATALOG.SVC_REF,
SERVICECATALOG.SVC_DESC,
SERVICECATALOG.SDG_ID,
STUDYGROUP1.SDG_REF,
STUDYGROUP1.SDG_DESC,
RECOVERYTXNLEDGER.SVC_PER_ID,
PERIOD1.PER_REF,
PERIOD1.PER_DESC,
RECOVERYTXNLEDGER.SVC_SCN_ID,
SCENARIO1.SCN_DESC,
RECOVERYTXNLEDGER.SVC_RATE,
RECOVERYTXNLEDGER.REC_TRANS_TYPE_ID,
RECOVERYTRANSTYPE.REC_TRANS_TYPE_NAME,
RECOVERYTXNLEDGER.CUST_ACCT_REF,
RECOVERYTXNLEDGER.ORG_REF,
ORGANIZATION.ORG_DESC,
STUDYGROUP.SDG_ID,
STUDYGROUP.SDG_REF,
STUDYGROUP.SDG_DESC,
RECOVERYTXNLEDGER.VOL_ID,
VOLUMECATALOG.VOL_REF,
VOLUMECATALOG.VOL_DESC,
RECOVERYTXNLEDGER.VOL_PER_ID,
PERIOD.PER_REF,
PERIOD.PER_DESC,
RECOVERYTXNLEDGER.VOL_SCN_ID,
SCENARIO.SCN_DESC,
RECOVERYTXNLEDGER.VOL_QTY
UNION
SELECT
NULL AS TXN_ID,
NULL AS REC_PROC_ID,
NULL AS RECORD_PROC_NAME,
NULL AS RECORD_PROC_TYPE_ID,
NULL AS RECORD_PROC_TYPE_NAME,
NULL AS RECORD_PROC_SEQUENCE_NUM,
NULL AS SERVICE_ID,
NULL AS SERVICE_REFERENCE,
NULL AS SERVICE_DESCRIPTION,
STUDYGROUP.SDG_ID AS SERVICE_STUDY_GROUP_ID,
STUDYGROUP.SDG_REF AS SERVICE_STUDY_GROUP_REF,
STUDYGROUP.SDG_DESC AS SERVICE_STUDY_GROUP_DESC,
NULL AS SERVICE_PERIOD_ID,
NULL AS SERVICE_PERIOD_REFERENCE,
NULL AS SERVICE_PERIOD_DESCRIPT,
NULL AS SERVICE_SCENARIO_ID,
NULL AS SERVICE_SCENARIO_DESC,
NULL AS SERVICE_RATE,
0 AS TRANS_TYPE_ID,
'Financials' AS TRANS_TYPE_NAME,
NULL AS CUSTOMER_ACCOUNT,
Financials.ORG_REF AS ORGANIZATION_REFERENCE,
Organization.ORG_DESC AS ORGANIZATION_DESCRIPTION,
StudyGroup.SDG_ID AS STUDY_GROUP_ID,
StudyGroup.SDG_REF AS STUDY_GROUP_REFERENCE,
StudyGroup.SDG_DESC AS STUDY_GROUP_DESCRIPT,
Sum(Financials.GL_AMOUNT) AS TRANSACTION_AMOUNT,
Financials.FIN_ID AS VOLUME_ID,
FINANCIALS.GLACCT_REF AS VOLUME_REFERENCE,
FINANCIALS.GLACCT_DESC AS VOLUME_DESCRIPTION,
Financials.FIN_PER_ID AS VOLUME_PERIOD_ID,
Period.PER_REF AS VOLUME_PERIOD_REFERENCE,
Period.PER_DESC AS VOLUME_PERIOD_DESCRIPT,
Financials.FIN_SCN_ID AS VOLUME_SCENARIO_ID,
Scenario.SCN_DESC AS VOLUME_SCENARIO_DESCRIPT,
NULL AS VOLUME_QUANTITY
FROM (((StudyGroup INNER JOIN Organization ON StudyGroup.SDG_ID = Organization.SDG_ID)
INNER JOIN Financials ON Organization.ORG_REF = Financials.ORG_REF)
INNER JOIN Scenario ON Financials.FIN_SCN_ID = Scenario.SCN_ID)
INNER JOIN Period ON Financials.FIN_PER_ID = Period.PER_ID
GROUP BY
NULL,
NULL,
NULL,
NULL,
NULL,
NULL,
NULL,
NULL,
NULL,
STUDYGROUP.SDG_ID,
STUDYGROUP.SDG_REF,
STUDYGROUP.SDG_DESC,
NULL,
NULL,
NULL,
NULL,
NULL,
NULL,
0,
'Financials',
NULL,
FINANCIALS.ORG_REF,
ORGANIZATION.ORG_DESC,
STUDYGROUP.SDG_ID,
STUDYGROUP.SDG_REF,
STUDYGROUP.SDG_DESC,
FINANCIALS.FIN_ID,
FINANCIALS.GLACCT_REF,
FINANCIALS.GLACCT_DESC,
FINANCIALS.FIN_PER_ID,
PERIOD.PER_REF,
PERIOD.PER_DESC,
FINANCIALS.FIN_SCN_ID,
SCENARIO.SCN_DESC,
NULL
我确实尝试用以下内容替换这两个文字：
CASE WHEN StudyGroup.SDG_ID >= 0 THEN 0 ELSE 0 END AS TRANS_TYPE_ID,
CASE WHEN StudyGroup.SDG_ID >= 0 THEN 'Financials' ELSE 'Financials' END AS TRANS_TYPE_NAME,
并在GROUP BY：
CASE WHEN StudyGroup.SDG_ID >= 0 THEN 0 ELSE 0 END,
CASE WHEN StudyGroup.SDG_ID >= 0 THEN 'Financials' ELSE 'Financials' END,
...谢谢
答案 0 :(得分：0)
我建议使用表别名，特别是对于像这样的较大查询。这使得阅读它变得容易得多。我稍微调整了你的第二个查询并添加了一些别名。然后我意识到你在查询中有两个相同的3列，你被他们多次分组。这不会影响结果，但会有点混乱。我猜这个问题出现在你的第二个查询中，所以在你将它添加到UNION之前，我会将其隔离并使其正常工作。
SELECT
NULL AS TXN_ID,
NULL AS REC_PROC_ID,
NULL AS RECORD_PROC_NAME,
NULL AS RECORD_PROC_TYPE_ID,
NULL AS RECORD_PROC_TYPE_NAME,
NULL AS RECORD_PROC_SEQUENCE_NUM,
NULL AS SERVICE_ID,
NULL AS SERVICE_REFERENCE,
NULL AS SERVICE_DESCRIPTION,
sg.SDG_ID AS SERVICE_STUDY_GROUP_ID,
sg.SDG_REF AS SERVICE_STUDY_GROUP_REF,
sg.SDG_DESC AS SERVICE_STUDY_GROUP_DESC,
NULL AS SERVICE_PERIOD_ID,
NULL AS SERVICE_PERIOD_REFERENCE,
NULL AS SERVICE_PERIOD_DESCRIPT,
NULL AS SERVICE_SCENARIO_ID,
NULL AS SERVICE_SCENARIO_DESC,
NULL AS SERVICE_RATE,
0 AS TRANS_TYPE_ID,
'Financials' AS TRANS_TYPE_NAME,
NULL AS CUSTOMER_ACCOUNT,
f.ORG_REF AS ORGANIZATION_REFERENCE,
o.ORG_DESC AS ORGANIZATION_DESCRIPTION,
sg.SDG_ID AS STUDY_GROUP_ID,
sg.SDG_REF AS STUDY_GROUP_REFERENCE,
sg.SDG_DESC AS STUDY_GROUP_DESCRIPT,
Sum(f.GL_AMOUNT) AS TRANSACTION_AMOUNT,
f.FIN_ID AS VOLUME_ID,
f.GLACCT_REF AS VOLUME_REFERENCE,
f.GLACCT_DESC AS VOLUME_DESCRIPTION,
f.FIN_PER_ID AS VOLUME_PERIOD_ID,
p.PER_REF AS VOLUME_PERIOD_REFERENCE,
p.PER_DESC AS VOLUME_PERIOD_DESCRIPT,
f.FIN_SCN_ID AS VOLUME_SCENARIO_ID,
s.SCN_DESC AS VOLUME_SCENARIO_DESCRIPT,
NULL AS VOLUME_QUANTITY
FROM StudyGroup sg
INNER JOIN Organization o ON sg.SDG_ID = o.SDG_ID
INNER JOIN Financials f ON o.ORG_REF = f.ORG_REF
INNER JOIN Scenario s ON f.FIN_SCN_ID = s.SCN_ID
INNER JOIN Period p ON f.FIN_PER_ID = p.PER_ID
GROUP BY
sg.SDG_ID,
sg.SDG_REF,
sg.SDG_DESC,
f.ORG_REF,
o.ORG_DESC,
f.FIN_ID,
f.GLACCT_REF,
f.GLACCT_DESC,
f.FIN_PER_ID,
p.PER_REF,
p.PER_DESC,
f.FIN_SCN_ID,
s.SCN_DESC
另外，我不确定您是否正在使用UNION，因为您想要消除两个查询之间的重复。如果没有，你将通过使用UNION ALL获得更好的性能，因此它不必检查重复项。