Question

我正在用libgdx开发一款游戏，但我陷入困境。所以我的SpriteBatch为具有相同纹理的数组中的所有矩形绘制，但我希望每一个都有自己的纹理。我的代码看起来像这样

    public class GameScreen implements Screen{

    final MrJetpack game;

    OrthographicCamera camera;
    SpriteBatch batch;
    ShapeRenderer rend;
    private Array<Rectangle> raindrops;

    Texture enemy1,enemy2,enemy3,enemy4,endScreen;
    TextureRegion[] enemys = new TextureRegion[4];

    private int random;


    public GameScreen(final MrJetpack game){

this.game = game;

camera = new OrthographicCamera();
camera.setToOrtho(false, 800, 480);

enemy1  = new Texture(Gdx.files.internal("boxk.png"));
enemy2  = new Texture(Gdx.files.internal("boxg.png"));
enemy3  = new Texture(Gdx.files.internal("kugel.png"));
enemy4  = new Texture(Gdx.files.internal("kugelk.png"));

enemys[0] = new TextureRegion(enemy1);      
enemys[1] = new TextureRegion(enemy2);    
enemys[2] = new TextureRegion(enemy3);     
enemys[3] = new TextureRegion(enemy4); 

raindrops = new Array<Rectangle>();

rend = new ShapeRenderer();
batch = new SpriteBatch();

   }


   @Override
   public void render(float delta) {
     // TODO Auto-generated method stub
//Gdx.gl.glClearColor(0, (float)148/255,(float) 255/255, 1);
  Gdx.gl.glClear(GL20.GL_COLOR_BUFFER_BIT);
  camera.update();




  batch.setProjectionMatrix(camera.combined);
  rend.begin(ShapeType.Filled);
  rend.rect(0, 0, 800, 10);
  rend.rect(0, 160, 800, 10);
  rend.rect(0, 320, 800, 10);
  rend.setColor(Color.ORANGE);
  rend.end();

  batch.begin();
  for(Rectangle raindrop: raindrops) {
      batch.draw(enemys[random], raindrop.x - 10, raindrop.y);
   }
  batch.end();


  if(TimeUtils.nanoTime() - lastDropTime > spawnTime){
      spawnRaindrop();  
      }
  Iterator<Rectangle> iter = raindrops.iterator();
  while(iter.hasNext()) {
     Rectangle raindrop = iter.next();
     raindrop.x -= 20 * Gdx.graphics.getDeltaTime();

     if(raindrop.x < 0) {
         spawnRaindrop();
         iter.remove();
     }
     }


    }


  private void spawnRaindrop() {
  Rectangle raindrop = new Rectangle();
  raindrop.x = 800;
  stages = MathUtils.random(1, 3);
  random = MathUtils.random(0, 3);
  raindrop.width = 30;
  raindrop.height = 53;
  raindrops.add(raindrop);
  lastDropTime = TimeUtils.nanoTime();
     }

所以实际发生的事情是，每当一个新的Rectangle在屏幕上产生，其他已经显示的那些就会改变纹理，所以每个Rectangle都有相同的纹理。任何解决方案或示例？

编辑：http://imgur.com/46ywYyy 对于理解我的问题的人来说，这是我的问题:) 就像你可以看到纹理正在改变所有其他矩形，但我希望每个人都有他们的静态纹理

Answer 1

他们告诉过你，有一种方法可以做到，但是我看到你不清楚，我会做或多或少的事情。

我会尝试让表单更像您代码中的内容。

注意这段代码可能有语法错误，因为我是从编辑器StackOverflow做的。

1-创建一个派生自精灵的类，例如：

public class SpriteRaindrop extends Sprite{ Rectangle raindrop = new Rectangle(); public SpriteRaindrop(Texture t, int srcWidth, int srcHeigth, float posX, float posY){ super(t, srcWidth, srcHeigth); raindrop.x = posX; raindrop.y = posY; raindrop.width = srcWidth; raindrop.height = srcHeigth; setPosition(posX, posY); } public void updateR(){ raindrod.x = getX(); raindrod.y = getY(); } }

您的代码包含任何更改

public class GameScreen implements Screen{ final MrJetpack game; OrthographicCamera camera; SpriteBatch batch; ShapeRenderer rend; private Array<SpriteRaindrop> raindrops; Texture enemy1,enemy2,enemy3,enemy4,endScreen; TextureRegion[] enemys = new TextureRegion[4]; private int random; public GameScreen(final MrJetpack game){ this.game = game; camera = new OrthographicCamera(); camera.setToOrtho(false, 800, 480); enemy1 = new Texture(Gdx.files.internal("boxk.png")); enemy2 = new Texture(Gdx.files.internal("boxg.png")); enemy3 = new Texture(Gdx.files.internal("kugel.png")); enemy4 = new Texture(Gdx.files.internal("kugelk.png")); enemys[0] = new TextureRegion(enemy1); enemys[1] = new TextureRegion(enemy2); enemys[2] = new TextureRegion(enemy3); enemys[3] = new TextureRegion(enemy4); raindrops = new Array<SpriteRaindrop>(); rend = new ShapeRenderer(); batch = new SpriteBatch(); } @Override public void render(float delta) { // TODO Auto-generated method stub //Gdx.gl.glClearColor(0, (float)148/255,(float) 255/255, 1); Gdx.gl.glClear(GL20.GL_COLOR_BUFFER_BIT); camera.update(); batch.setProjectionMatrix(camera.combined); rend.begin(ShapeType.Filled); rend.rect(0, 0, 800, 10); rend.rect(0, 160, 800, 10); rend.rect(0, 320, 800, 10); rend.setColor(Color.ORANGE); rend.end(); batch.begin(); for(SpriteRaindrop raindrop: raindrops) { //raindrop.translatex(-10f); //what is raindrop.y value raindrop.updateR(); raindrop.draw(batch); } batch.end(); if(TimeUtils.nanoTime() - lastDropTime > spawnTime){ spawnRaindrop(); } Iterator<SpriteRaindrop> iter = raindrops.iterator(); while(iter.hasNext()) { SpriteRaindrop raindrop = iter.next(); raindrop.translateX(-20f * Gdx.graphics.getDeltaTime()); if(raindrop.getX() < 0) { spawnRaindrop(); iter.remove(); } } } private void spawnRaindrop() { stages = MathUtils.random(1, 3); random = MathUtils.random(0, 3); lastDropTime = TimeUtils.nanoTime(); SpriteRaindrop raindrop = new SpriteRaindrop(enemys[random], 30, 53, 800, 0); raindrops.add(raindrop); }

这只是一个想法，但我认为它可行，我希望你能帮忙

Answer 2

变量random对于class是全局的，一旦新的sprite产生，它就会将值设置为新的随机值，并且所有这些都是通过以下方式绘制的：

batch.draw（enemys [random]，raindrop.x - 10，raindrop.y）;

您需要跟踪每个实例的位置。

Libgdx渲染矩形阵列不同的纹理

2 个答案: