我正在寻找从RGB到HSV的色彩空间转换器，特别是两个色彩空间的0到255范围。
答案 0 :(得分：118)
我已经使用了很长时间了 - 不知道它们来自何处...请注意，输入和输出除了以度为单位的角度外，都在0到1.0之间。
注意：此代码对输入没有真正的健全性检查。谨慎行事！
typedef struct {
double r; // a fraction between 0 and 1
double g; // a fraction between 0 and 1
double b; // a fraction between 0 and 1
} rgb;
typedef struct {
double h; // angle in degrees
double s; // a fraction between 0 and 1
double v; // a fraction between 0 and 1
} hsv;
static hsv rgb2hsv(rgb in);
static rgb hsv2rgb(hsv in);
hsv rgb2hsv(rgb in)
{
hsv out;
double min, max, delta;
min = in.r < in.g ? in.r : in.g;
min = min < in.b ? min : in.b;
max = in.r > in.g ? in.r : in.g;
max = max > in.b ? max : in.b;
out.v = max; // v
delta = max - min;
if (delta < 0.00001)
{
out.s = 0;
out.h = 0; // undefined, maybe nan?
return out;
}
if( max > 0.0 ) { // NOTE: if Max is == 0, this divide would cause a crash
out.s = (delta / max); // s
} else {
// if max is 0, then r = g = b = 0
// s = 0, h is undefined
out.s = 0.0;
out.h = NAN; // its now undefined
return out;
}
if( in.r >= max ) // > is bogus, just keeps compilor happy
out.h = ( in.g - in.b ) / delta; // between yellow & magenta
else
if( in.g >= max )
out.h = 2.0 + ( in.b - in.r ) / delta; // between cyan & yellow
else
out.h = 4.0 + ( in.r - in.g ) / delta; // between magenta & cyan
out.h *= 60.0; // degrees
if( out.h < 0.0 )
out.h += 360.0;
return out;
}
rgb hsv2rgb(hsv in)
{
double hh, p, q, t, ff;
long i;
rgb out;
if(in.s <= 0.0) { // < is bogus, just shuts up warnings
out.r = in.v;
out.g = in.v;
out.b = in.v;
return out;
}
hh = in.h;
if(hh >= 360.0) hh = 0.0;
hh /= 60.0;
i = (long)hh;
ff = hh - i;
p = in.v * (1.0 - in.s);
q = in.v * (1.0 - (in.s * ff));
t = in.v * (1.0 - (in.s * (1.0 - ff)));
switch(i) {
case 0:
out.r = in.v;
out.g = t;
out.b = p;
break;
case 1:
out.r = q;
out.g = in.v;
out.b = p;
break;
case 2:
out.r = p;
out.g = in.v;
out.b = t;
break;
case 3:
out.r = p;
out.g = q;
out.b = in.v;
break;
case 4:
out.r = t;
out.g = p;
out.b = in.v;
break;
case 5:
default:
out.r = in.v;
out.g = p;
out.b = q;
break;
}
return out;
}
答案 1 :(得分：32)
您也可以尝试不使用浮点数（更快但不太准确）的代码：
typedef struct RgbColor
{
unsigned char r;
unsigned char g;
unsigned char b;
} RgbColor;
typedef struct HsvColor
{
unsigned char h;
unsigned char s;
unsigned char v;
} HsvColor;
RgbColor HsvToRgb(HsvColor hsv)
{
RgbColor rgb;
unsigned char region, remainder, p, q, t;
if (hsv.s == 0)
{
rgb.r = hsv.v;
rgb.g = hsv.v;
rgb.b = hsv.v;
return rgb;
}
region = hsv.h / 43;
remainder = (hsv.h - (region * 43)) * 6;
p = (hsv.v * (255 - hsv.s)) >> 8;
q = (hsv.v * (255 - ((hsv.s * remainder) >> 8))) >> 8;
t = (hsv.v * (255 - ((hsv.s * (255 - remainder)) >> 8))) >> 8;
switch (region)
{
case 0:
rgb.r = hsv.v; rgb.g = t; rgb.b = p;
break;
case 1:
rgb.r = q; rgb.g = hsv.v; rgb.b = p;
break;
case 2:
rgb.r = p; rgb.g = hsv.v; rgb.b = t;
break;
case 3:
rgb.r = p; rgb.g = q; rgb.b = hsv.v;
break;
case 4:
rgb.r = t; rgb.g = p; rgb.b = hsv.v;
break;
default:
rgb.r = hsv.v; rgb.g = p; rgb.b = q;
break;
}
return rgb;
}
HsvColor RgbToHsv(RgbColor rgb)
{
HsvColor hsv;
unsigned char rgbMin, rgbMax;
rgbMin = rgb.r < rgb.g ? (rgb.r < rgb.b ? rgb.r : rgb.b) : (rgb.g < rgb.b ? rgb.g : rgb.b);
rgbMax = rgb.r > rgb.g ? (rgb.r > rgb.b ? rgb.r : rgb.b) : (rgb.g > rgb.b ? rgb.g : rgb.b);
hsv.v = rgbMax;
if (hsv.v == 0)
{
hsv.h = 0;
hsv.s = 0;
return hsv;
}
hsv.s = 255 * long(rgbMax - rgbMin) / hsv.v;
if (hsv.s == 0)
{
hsv.h = 0;
return hsv;
}
if (rgbMax == rgb.r)
hsv.h = 0 + 43 * (rgb.g - rgb.b) / (rgbMax - rgbMin);
else if (rgbMax == rgb.g)
hsv.h = 85 + 43 * (rgb.b - rgb.r) / (rgbMax - rgbMin);
else
hsv.h = 171 + 43 * (rgb.r - rgb.g) / (rgbMax - rgbMin);
return hsv;
}
注意此算法使用0x00 - 0xFF作为其范围（不 0-360）。
（Source）功能
答案 2 :(得分：22)
我在HLSL中为我们的渲染引擎写了这个，它没有条件：
float3 HSV2RGB( float3 _HSV )
{
_HSV.x = fmod( 100.0 + _HSV.x, 1.0 ); // Ensure [0,1[
float HueSlice = 6.0 * _HSV.x; // In [0,6[
float HueSliceInteger = floor( HueSlice );
float HueSliceInterpolant = HueSlice - HueSliceInteger; // In [0,1[ for each hue slice
float3 TempRGB = float3( _HSV.z * (1.0 - _HSV.y),
_HSV.z * (1.0 - _HSV.y * HueSliceInterpolant),
_HSV.z * (1.0 - _HSV.y * (1.0 - HueSliceInterpolant)) );
// The idea here to avoid conditions is to notice that the conversion code can be rewritten:
// if ( var_i == 0 ) { R = V ; G = TempRGB.z ; B = TempRGB.x }
// else if ( var_i == 2 ) { R = TempRGB.x ; G = V ; B = TempRGB.z }
// else if ( var_i == 4 ) { R = TempRGB.z ; G = TempRGB.x ; B = V }
//
// else if ( var_i == 1 ) { R = TempRGB.y ; G = V ; B = TempRGB.x }
// else if ( var_i == 3 ) { R = TempRGB.x ; G = TempRGB.y ; B = V }
// else if ( var_i == 5 ) { R = V ; G = TempRGB.x ; B = TempRGB.y }
//
// This shows several things:
// . A separation between even and odd slices
// . If slices (0,2,4) and (1,3,5) can be rewritten as basically being slices (0,1,2) then
// the operation simply amounts to performing a "rotate right" on the RGB components
// . The base value to rotate is either (V, B, R) for even slices or (G, V, R) for odd slices
//
float IsOddSlice = fmod( HueSliceInteger, 2.0 ); // 0 if even (slices 0, 2, 4), 1 if odd (slices 1, 3, 5)
float ThreeSliceSelector = 0.5 * (HueSliceInteger - IsOddSlice); // (0, 1, 2) corresponding to slices (0, 2, 4) and (1, 3, 5)
float3 ScrollingRGBForEvenSlices = float3( _HSV.z, TempRGB.zx ); // (V, Temp Blue, Temp Red) for even slices (0, 2, 4)
float3 ScrollingRGBForOddSlices = float3( TempRGB.y, _HSV.z, TempRGB.x ); // (Temp Green, V, Temp Red) for odd slices (1, 3, 5)
float3 ScrollingRGB = lerp( ScrollingRGBForEvenSlices, ScrollingRGBForOddSlices, IsOddSlice );
float IsNotFirstSlice = saturate( ThreeSliceSelector ); // 1 if NOT the first slice (true for slices 1 and 2)
float IsNotSecondSlice = saturate( ThreeSliceSelector-1.0 ); // 1 if NOT the first or second slice (true only for slice 2)
return lerp( ScrollingRGB.xyz, lerp( ScrollingRGB.zxy, ScrollingRGB.yzx, IsNotSecondSlice ), IsNotFirstSlice ); // Make the RGB rotate right depending on final slice index
}
答案 3 :(得分：8)
这应该在这里： 无论如何它都有用。与上述相比，它看起来很不错。
hlsl代码
float3 Hue(float H)
{
half R = abs(H * 6 - 3) - 1;
half G = 2 - abs(H * 6 - 2);
half B = 2 - abs(H * 6 - 4);
return saturate(half3(R,G,B));
}
half4 HSVtoRGB(in half3 HSV)
{
return half4(((Hue(HSV.x) - 1) * HSV.y + 1) * HSV.z,1);
}
float3是16位精度vector3数据类型，即float3 hue（）返回数据类型（x，y，z），例如（r，g，b），半精度相同，8位，float4是（r，g，b，a）4个值。
答案 4 :(得分：5)
这是基于Agoston的 Computer Graphics and Geometric Modeling: Implementation and Algorithms p的C实现。 304， H ∈[0,360]和 S ， V ∈[0,1]。
X Y * * * /path/to/script1.py && /bin/date '+%Y%m%d%H%M script one ran' >> /home/jrambo/script1.log
X Y * * * /path/to/script2.py && /bin/date '+%Y%m%d%H%M script two ran' >> /home/jrambo/script2.log
答案 5 :(得分：4)
typedef struct RgbColor
{
unsigned char r;
unsigned char g;
unsigned char b;
} RgbColor;
typedef struct HsvColor
{
unsigned char h;
unsigned char s;
unsigned char v;
} HsvColor;
RgbColor HsvToRgb(HsvColor hsv)
{
RgbColor rgb;
unsigned char region, p, q, t;
unsigned int h, s, v, remainder;
if (hsv.s == 0)
{
rgb.r = hsv.v;
rgb.g = hsv.v;
rgb.b = hsv.v;
return rgb;
}
// converting to 16 bit to prevent overflow
h = hsv.h;
s = hsv.s;
v = hsv.v;
region = h / 43;
remainder = (h - (region * 43)) * 6;
p = (v * (255 - s)) >> 8;
q = (v * (255 - ((s * remainder) >> 8))) >> 8;
t = (v * (255 - ((s * (255 - remainder)) >> 8))) >> 8;
switch (region)
{
case 0:
rgb.r = v;
rgb.g = t;
rgb.b = p;
break;
case 1:
rgb.r = q;
rgb.g = v;
rgb.b = p;
break;
case 2:
rgb.r = p;
rgb.g = v;
rgb.b = t;
break;
case 3:
rgb.r = p;
rgb.g = q;
rgb.b = v;
break;
case 4:
rgb.r = t;
rgb.g = p;
rgb.b = v;
break;
default:
rgb.r = v;
rgb.g = p;
rgb.b = q;
break;
}
return rgb;
}
HsvColor RgbToHsv(RgbColor rgb)
{
HsvColor hsv;
unsigned char rgbMin, rgbMax;
rgbMin = rgb.r < rgb.g ? (rgb.r < rgb.b ? rgb.r : rgb.b) : (rgb.g < rgb.b ? rgb.g : rgb.b);
rgbMax = rgb.r > rgb.g ? (rgb.r > rgb.b ? rgb.r : rgb.b) : (rgb.g > rgb.b ? rgb.g : rgb.b);
hsv.v = rgbMax;
if (hsv.v == 0)
{
hsv.h = 0;
hsv.s = 0;
return hsv;
}
hsv.s = 255 * ((long)(rgbMax - rgbMin)) / hsv.v;
if (hsv.s == 0)
{
hsv.h = 0;
return hsv;
}
if (rgbMax == rgb.r)
hsv.h = 0 + 43 * (rgb.g - rgb.b) / (rgbMax - rgbMin);
else if (rgbMax == rgb.g)
hsv.h = 85 + 43 * (rgb.b - rgb.r) / (rgbMax - rgbMin);
else
hsv.h = 171 + 43 * (rgb.r - rgb.g) / (rgbMax - rgbMin);
return hsv;
}
答案 6 :(得分：4)
这不是C，但它确实有效。我在这里看到的所有其他方法都可以通过将所有方法都包装成六边形的一部分来实现，并且近似于角度＆＃34;从那以后。相反，从使用余弦的不同方程开始，并求解h s和v，你得到hsv和rgb之间更好的关系，并且补间变得更平滑（代价是它更慢）。
假设一切都是浮点数。如果r g和b从0变为1，则h从0变为2pi，v从0变为4/3，s从0变为2/3。
以下代码是用Lua编写的。它很容易翻译成其他任何东西。
local hsv do
hsv ={}
local atan2 =math.atan2
local cos =math.cos
local sin =math.sin
function hsv.fromrgb(r,b,g)
local c=r+g+b
if c<1e-4 then
return 0,2/3,0
else
local p=2*(b*b+g*g+r*r-g*r-b*g-b*r)^0.5
local h=atan2(b-g,(2*r-b-g)/3^0.5)
local s=p/(c+p)
local v=(c+p)/3
return h,s,v
end
end
function hsv.torgb(h,s,v)
local r=v*(1+s*(cos(h)-1))
local g=v*(1+s*(cos(h-2.09439)-1))
local b=v*(1+s*(cos(h+2.09439)-1))
return r,g,b
end
function hsv.tween(h0,s0,v0,h1,s1,v1,t)
local dh=(h1-h0+3.14159)%6.28318-3.14159
local h=h0+t*dh
local s=s0+t*(s1-s0)
local v=v0+t*(v1-v0)
return h,s,v
end
end
答案 7 :(得分：2)
基于Patapoms的GLSL Shader版本回答：
vec3 HSV2RGB( vec3 hsv )
{
hsv.x = mod( 100.0 + hsv.x, 1.0 ); // Ensure [0,1[
float HueSlice = 6.0 * hsv.x; // In [0,6[
float HueSliceInteger = floor( HueSlice );
float HueSliceInterpolant = HueSlice - HueSliceInteger; // In [0,1[ for each hue slice
vec3 TempRGB = vec3( hsv.z * (1.0 - hsv.y), hsv.z * (1.0 - hsv.y * HueSliceInterpolant), hsv.z * (1.0 - hsv.y * (1.0 - HueSliceInterpolant)) );
float IsOddSlice = mod( HueSliceInteger, 2.0 ); // 0 if even (slices 0, 2, 4), 1 if odd (slices 1, 3, 5)
float ThreeSliceSelector = 0.5 * (HueSliceInteger - IsOddSlice); // (0, 1, 2) corresponding to slices (0, 2, 4) and (1, 3, 5)
vec3 ScrollingRGBForEvenSlices = vec3( hsv.z, TempRGB.zx ); // (V, Temp Blue, Temp Red) for even slices (0, 2, 4)
vec3 ScrollingRGBForOddSlices = vec3( TempRGB.y, hsv.z, TempRGB.x ); // (Temp Green, V, Temp Red) for odd slices (1, 3, 5)
vec3 ScrollingRGB = mix( ScrollingRGBForEvenSlices, ScrollingRGBForOddSlices, IsOddSlice );
float IsNotFirstSlice = clamp( ThreeSliceSelector, 0.0,1.0 ); // 1 if NOT the first slice (true for slices 1 and 2)
float IsNotSecondSlice = clamp( ThreeSliceSelector-1.0, 0.0,1. ); // 1 if NOT the first or second slice (true only for slice 2)
return mix( ScrollingRGB.xyz, mix( ScrollingRGB.zxy, ScrollingRGB.yzx, IsNotSecondSlice ), IsNotFirstSlice ); // Make the RGB rotate right depending on final slice index
}
答案 8 :(得分：0)
This link包含您想要的公式。如果你想快速的话，那就是性能问题（数值技术）。
答案 9 :(得分：0)
这是我今天早上写的基于与上面几乎相同的数学的那个：
/* math adapted from: http://www.rapidtables.com/convert/color/rgb-to-hsl.htm
* reasonably optimized for speed, without going crazy */
void rgb_to_hsv (int r, int g, int b, float *r_h, float *r_s, float *r_v) {
float rp, gp, bp, cmax, cmin, delta, l;
int cmaxwhich, cminwhich;
rp = ((float) r) / 255;
gp = ((float) g) / 255;
bp = ((float) b) / 255;
//debug ("rgb=%d,%d,%d rgbprime=%f,%f,%f", r, g, b, rp, gp, bp);
cmax = rp;
cmaxwhich = 0; /* faster comparison afterwards */
if (gp > cmax) { cmax = gp; cmaxwhich = 1; }
if (bp > cmax) { cmax = bp; cmaxwhich = 2; }
cmin = rp;
cminwhich = 0;
if (gp < cmin) { cmin = gp; cminwhich = 1; }
if (bp < cmin) { cmin = bp; cminwhich = 2; }
//debug ("cmin=%f,cmax=%f", cmin, cmax);
delta = cmax - cmin;
/* HUE */
if (delta == 0) {
*r_h = 0;
} else {
switch (cmaxwhich) {
case 0: /* cmax == rp */
*r_h = HUE_ANGLE * (fmod ((gp - bp) / delta, 6));
break;
case 1: /* cmax == gp */
*r_h = HUE_ANGLE * (((bp - rp) / delta) + 2);
break;
case 2: /* cmax == bp */
*r_h = HUE_ANGLE * (((rp - gp) / delta) + 4);
break;
}
if (*r_h < 0)
*r_h += 360;
}
/* LIGHTNESS/VALUE */
//l = (cmax + cmin) / 2;
*r_v = cmax;
/* SATURATION */
/*if (delta == 0) {
*r_s = 0;
} else {
*r_s = delta / (1 - fabs (1 - (2 * (l - 1))));
}*/
if (cmax == 0) {
*r_s = 0;
} else {
*r_s = delta / cmax;
}
//debug ("rgb=%d,%d,%d ---> hsv=%f,%f,%f", r, g, b, *r_h, *r_s, *r_v);
}
void hsv_to_rgb (float h, float s, float v, int *r_r, int *r_g, int *r_b) {
if (h > 360)
h -= 360;
if (h < 0)
h += 360;
h = CLAMP (h, 0, 360);
s = CLAMP (s, 0, 1);
v = CLAMP (v, 0, 1);
float c = v * s;
float x = c * (1 - fabsf (fmod ((h / HUE_ANGLE), 2) - 1));
float m = v - c;
float rp, gp, bp;
int a = h / 60;
//debug ("h=%f, a=%d", h, a);
switch (a) {
case 0:
rp = c;
gp = x;
bp = 0;
break;
case 1:
rp = x;
gp = c;
bp = 0;
break;
case 2:
rp = 0;
gp = c;
bp = x;
break;
case 3:
rp = 0;
gp = x;
bp = c;
break;
case 4:
rp = x;
gp = 0;
bp = c;
break;
default: // case 5:
rp = c;
gp = 0;
bp = x;
break;
}
*r_r = (rp + m) * 255;
*r_g = (gp + m) * 255;
*r_b = (bp + m) * 255;
//debug ("hsv=%f,%f,%f, ---> rgb=%d,%d,%d", h, s, v, *r_r, *r_g, *r_b);
}
答案 10 :(得分：0)
我创建了一个可能更快的实现，使用0-1范围用于RGBS和V和0-6范围用于Hue（避免除法），并将案例分为两类：
coll/doc对于0-255范围，只需* 255.0f + 0.5f并将其分配给无符号字符（或除以255.0以获得相反的结果）。
答案 11 :(得分：0)
我不是C ++开发人员，所以我将不提供代码。但是，我可以提供目前发现的简单 hsv2rgb 算法（rgb2hsv here）-我用描述HSV和HLS更新Wiki。主要的改进是，我仔细观察了r，g，b作为色调函数，并引入了更简单的形状函数来描述它们（不失精确性）。 算法-输入时，我们有：h（0-255），s（0-255），v（0-255）
r = 255*f(5), g = 255*f(3), b = 255*f(1)
我们使用如下所述的函数f
f(n) = v/255 - (v/255)*(s/255)*max(min(k,4-k,1),0)
其中（mod可以返回小数部分； k是浮点数）
k = (n+h*360/(255*60)) mod 6;
答案 12 :(得分：0)
// This pair of functions convert HSL to RGB and vice-versa.
// It's pretty optimized for execution speed
typedef unsigned char BYTE
typedef struct _RGB
{
BYTE R;
BYTE G;
BYTE B;
} RGB, *pRGB;
typedef struct _HSL
{
float H; // color Hue (0.0 to 360.0 degrees)
float S; // color Saturation (0.0 to 1.0)
float L; // Luminance (0.0 to 1.0)
float V; // Value (0.0 to 1.0)
} HSL, *pHSL;
float *fMin (float *a, float *b)
{
return *a <= *b? a : b;
}
float *fMax (float *a, float *b)
{
return *a >= *b? a : b;
}
void RGBtoHSL (pRGB rgb, pHSL hsl)
{
// See https://en.wikipedia.org/wiki/HSL_and_HSV
// rgb->R, rgb->G, rgb->B: [0 to 255]
float r = (float) rgb->R / 255;
float g = (float) rgb->G / 255;
float b = (float) rgb->B / 255;
float *min = fMin(fMin(&r, &g), &b);
float *max = fMax(fMax(&r, &g), &b);
float delta = *max - *min;
// L, V [0.0 to 1.0]
hsl->L = (*max + *min)/2;
hsl->V = *max;
// Special case for H and S
if (delta == 0)
{
hsl->H = 0.0f;
hsl->S = 0.0f;
}
else
{
// Special case for S
if((*max == 0) || (*min == 1))
hsl->S = 0;
else
// S [0.0 to 1.0]
hsl->S = (2 * *max - 2*hsl->L)/(1 - fabsf(2*hsl->L - 1));
// H [0.0 to 360.0]
if (max == &r) hsl->H = fmod((g - b)/delta, 6); // max is R
else if (max == &g) hsl->H = (b - r)/delta + 2; // max is G
else hsl->H = (r - g)/delta + 4; // max is B
hsl->H *= 60;
}
}
void HSLtoRGB (pHSL hsl, pRGB rgb)
{
// See https://en.wikipedia.org/wiki/HSL_and_HSV
float a, k, fm1, fp1, f1, f2, *f3;
// L, V, S: [0.0 to 1.0]
// rgb->R, rgb->G, rgb->B: [0 to 255]
fm1 = -1;
fp1 = 1;
f1 = 1-hsl->L;
a = hsl->S * *fMin(&hsl->L, &f1);
k = fmod(0 + hsl->H/30, 12);
f1 = k - 3;
f2 = 9 - k;
f3 = fMin(fMin(&f1, &f2), &fp1) ;
rgb->R = (BYTE) (255 * (hsl->L - a * *fMax(f3, &fm1)));
k = fmod(8 + hsl->H/30, 12);
f1 = k - 3;
f2 = 9 - k;
f3 = fMin(fMin(&f1, &f2), &fp1) ;
rgb->G = (BYTE) (255 * (hsl->L - a * *fMax(f3, &fm1)));
k = fmod(4 + hsl->H/30, 12);
f1 = k - 3;
f2 = 9 - k;
f3 = fMin(fMin(&f1, &f2), &fp1) ;
rgb->B = (BYTE) (255 * (hsl->L - a * *fMax(f3, &fm1)));
}
答案 13 :(得分：0)
这里是online converter，其中包含解释了所有颜色转换算法的文章。
您可能希望使用现成的C版本，但是应用起来应该不会太久，它可以帮助其他尝试使用另一种语言或另一种色彩空间进行相同操作的人。
答案 14 :(得分：-1)
How is this algorithm-
void RGB_to_HSV(float R, float G, float B){
float H, S, V;
float Max, Min;
Max = max(R, G, B);
Min= min(R, G, B);
V= Max;
if(Max == 0){
s=0;
}
else{
s= Max-Min/Max;
}
if(s==0){
H = undefined;
}
else{
if(R == Max){
H = (G-B)*60/Max-Min;
if(H<0)
H+ = 360;
}
elseif(G==Max){
H = (B-R)*(60+120)/Max-Min;
}
else{
H = (R-G)*(60+240)/Max-Min;
}
}
printf('H S V');
}