我希望将我表单中所有选中的复选框都放到数组中。
这就是我所做的。
$("div.category-panel input:checked").next ('label').text();
完美地获取所有选中的复选框,但它只是将它们一起显示为一个文本。例如,checkbox1
,checkbox2
和checkbox3
(如果已选中)将显示为checkbox1checkbox2checkbox3
。
我希望在数组中获得这些不同的复选框,以便我可以使用它们。
$('.submit').on("click", function(e) {
//got all checked checkboxes into 'children'.
children = $("div.category-panel input:checked").next ('label').text();
//Put in array.
var array = [];
var i = 0;
$.each(children, function(key, value){
array.push($(this).text());
});
//Show the array.
for (var i = 0; i < array.length; i++) {
console.log(array[i]);
}
});
HTML,以防万一: -
<div class="category-panel">
<input type="checkbox" name="name_service2" id="tid-46" value="46" checked="checked"> <label class="option" for="edit-tid-46">CheckBox1</label>
<input type="checkbox" name="name_service3" id="tid-47" value="47" checked="checked"> <label class="option" for="edit-tid-47">CheckBox2</label>
<input type="checkbox" name="name_service4" id="tid-44" value="44" checked="checked"> <label class="option" for="edit-tid-44">CheckBox3</label>
<input type="checkbox" name="name_service5" id="tid-48" value="48" checked="checked"> <label class="option" for="edit-tid-48">CheckBox4</label>
</div>
答案 0 :(得分:2)
您可以使用.map()之类的
$('.submit').on("click", function (e) {
//got all checked checkboxes into 'children'.
var array = $("div.category-panel input:checked").next('label').map(function(){
return $(this).text();
}).get();
//Show the array.
for (var i = 0; i < array.length; i++) {
console.log(array[i]);
}
});
$('.submit').on("click", function(e) {
//got all checked checkboxes into 'children'.
var array = $("div.category-panel input:checked").next('label').map(function() {
return $(this).text();
}).get();
//Show the array.
for (var i = 0; i < array.length; i++) {
console.log(array[i]);
}
});
&#13;
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.11.1/jquery.min.js"></script>
<div class="category-panel">
<input type="checkbox" name="name_service2" id="tid-46" value="46" checked="checked" />
<label class="option" for="edit-tid-46">CheckBox1</label>
<input type="checkbox" name="name_service3" id="tid-47" value="47" checked="checked" />
<label class="option" for="edit-tid-47">CheckBox2</label>
<input type="checkbox" name="name_service4" id="tid-44" value="44" checked="checked" />
<label class="option" for="edit-tid-44">CheckBox3</label>
<input type="checkbox" name="name_service5" id="tid-48" value="48" checked="checked" />
<label class="option" for="edit-tid-48">CheckBox4</label>
</div>
<button class="submit">submit</button>
&#13;
在您的情况下,children
是一个字符串,其中包含所有标签的连接文本,这些标签是已选中复选框的下一个兄弟;
答案 1 :(得分:1)
您需要使用.map()
函数将所有标签文本作为对象。然后使用.get()
将它们放入数组:
$("div.category-panel input:checked").next('label').map(function(){
return $(this).text();
}).get();// ["checkbox1","checkbox2" ,"checkbox3"]
如果您希望将它们作为逗号分隔值,请在.join()
.get()
$("div.category-panel input:checked").next('label').map(function(){
return $(this).text();
}).get().join();// "checkbox1, checkbox2 ,checkbox3"
答案 2 :(得分:1)
<input type="checkbox" name="name_service2" id="tid-46" value="46" checked="checked" /> <label class="option" for="edit-tid-46">A Value</label>
<input type="checkbox" name="name_service3" id="tid-47" value="47" checked="checked" /> <label class="option" for="edit-tid-47">A Value</label>
<input type="checkbox" name="name_service4" id="tid-44" value="44" checked="checked" /> <label class="option" for="edit-tid-44">A Value</label>
<input type="checkbox" name="name_service5" id="tid-48" value="48" checked="checked" /> <label class="option" for="edit-tid-48">A Value</label>
$('.submit').on("click", function(e) {
//got all checked checkboxes into 'children'.
children = $("div.category-panel input:checked").next ('label');
//Put in array.
var array = [];
$.each(children, function(){
array.push($(this).text());
});
//Show the array.
$(array).each(function(){
console.log(this.toString());
});
});