我是jquery的noob。我正在努力做到这一点:
我需要在鼠标悬停时单独折叠每个菜单.2菜单同时崩溃的问题! 我确定它是基本的东西,但我似乎无法弄明白。 请帮忙。谢谢
$(document).ready(function() {
$(".lead-title-index").hover(function() {
$(".featured-content").slideDown("slow");
});
});

.featured-content {
width: 200px;
height: 400px;
display: none;
background: #2E2E2E;
}
.lead-title-index {
background: #FFBF00;
display: block;
margin-bottom: 0px;
position: relative;
color: #000;
font-size: 14px;
width: 200px;
height: 70px;
}

<script src="https://cdnjs.cloudflare.com/ajax/libs/knockout/3.2.0/knockout-min.js"></script>
<script src="https://cdnjs.cloudflare.com/ajax/libs/d3/3.4.11/d3.min.js"></script>
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.0.1/jquery.min.js"></script>
<div class="col-md-15 col-sm-3">
<div class="lead-title-index">
</div>
<article id="video" class="featured-content">
<div class="promo-text">
</div>
</article>
</div>
<div class="col-md-15 col-sm-3">
<div class="lead-title-index">
</div>
<article id="video" class="featured-content">
<div class="promo-text">
</div>
</article>
</div>
&#13;
答案 0 :(得分:0)
您需要在所选项目之后使用下一个项目,如下所示
$(document).ready(function() {
$(".lead-title-index").hover(function() {
$(this).next(".featured-content").slideDown("slow");
});
});