Question

我有两个我试图去上班的课程。 twitter.py假设是Tweet.py的经理。 Twitter添加了新的推文，查看最近5条最近的推文，其中包含最接近的时间单位：

Recent Tweets
------------
Dave - 5min
Hello world!

Tweet为twitter.py定义要管理的类Tweet。 Tweet类有三个数据属性：__ author，__ user和__text以及四个方法：get_author，get_text和get_age（特殊，因为它假设计算__age的当前时间和值之间的差异，然后将其作为字符串返回）。应该允许第三个选择在推文中搜索任何关键字。

前：

What would you like to search for? Cat

Search results 
--------------
Daniel - 2hrs

My cat is fluffy.

twitter.py - http://pastebin.com/mQ9CCu3H

import Tweet
import pickle

MAKE = 1
VIEW = 2
SEARCH = 3
QUIT = 4

FILENAME = 'tweets.dat'

def main():
    mytweets = load_tweets()

    choice = 0

    while choice != QUIT:
        choice = get_menu_choice()

        if choice == MAKE:
            add(mytweets)
        elif choice == VIEW:
            recent(mytweets)
        elif choice == SEARCH:
            find(mytweets)
        else:
            print("\nThanks for using the Twitter manager!")

    save_tweets(mytweets)

def load_tweets():
    try:
        input_file = open(FILENAME, 'rb')

        tweet_dct = pickle.load(input_file)

        input_file.close()

    except IOError:
        tweet_dct = {}

    return tweet_dct

def get_menu_choice():
    print()
    print('Tweet Menu')
    print("----------")
    print("1. Make a Tweet")
    print("2. View Recent Tweets")
    print("3. Search Tweets")
    print("4. Quit")
    print()


    try:
        choice = int(input("What would you like to do? "))
        if choice < MAKE or choice > QUIT:
            print("Please select a valid option./n")

    except ValueError:
        print("Please enter a numeric value. /n")

    return choice

def add(mytweets):

    author = input("\nWhat is your name? ")
    while True:
        text = input("what would you like to tweet? ")
        if len(text) > 140:
            print("\nTweets can only be 140 characters!")
            continue
        else:
            break




    entry = Tweet.Tweet(author, text)

    print("\nYour tweet has been saved!")

def recent(mytweets):
    print("\nRecent Tweets")
    print("---------------")
    if len(mytweets) < 1:
        print("There are no recent tweets.")
    else:
        print(mytweets(-5))

def find(mytweets):


    author = input("What would you like to search for? ")
    if author in mytweets:
        print("\nSearch Results")
        print("----------------")
        print(Tweet.Tweet.get_author, - Tweet.Tweet.get_age)
        print(Tweet.Tweet.get_text)
    else:
        print("\nSearch Results")
        print("----------------")
        print("No tweets contained ", Tweet.Tweet.get_author, Tweet.Tweet.get_text)

def save_tweets(mytweets):
    output_file = open(FILENAME, 'wb')

    pickle.dump(mytweets, output_file)

    output_file.close()

main()

Tweet.py - http://pastebin.com/AcmprzAT

import time

class Tweet:

    def __init__(self, author, text):

        self.__author = author
        self.__text = text
        self.__age = time.time()

    def get_author(self):

        return self.__author

    def get_text(self):

        return self.__text

    def get_age(self):
        now = time.time()

        difference = now - self.__time

        hours = difference // 3600

        difference = difference % 3600

        minutes = difference // 60

        seconds = difference % 60


        # Truncate units of time and convert them to strings for output
        hours = str(int(hours))
        minutes = str(int(minutes))
        seconds = str(int(seconds))

        # Return formatted units of time
        return hours + ":" + minutes + ":" + seconds

我遇到的问题：

在做出选择2时，它跳转到消息而不是显示字典中的任何推文。我没有添加任何推文吗？
在做出选择3时，如果没有任何推文，它会显示所谓的消息 - No tweets contained <function Tweet.get_author at 0x02E20348> <function Tweet.get_text at 0x02E20390>

所以，我猜我没有在列表中添加任何推文。我是对的吗？

Answer 1

在twitter.py文件的add方法中：

mytweets.update({author:text})

您没有将推文添加到任何字典或列表中，您基本上只是阅读用户输入并创建Tweet类的实例。

所以，你需要添加如下内容：

    [self.navigationBar setBackgroundImage:[UIImage new]
                     forBarMetrics:UIBarMetricsDefault];
    self.navigationBar.shadowImage = [UIImage new];
    self.navigationBar.translucent = YES;

Python编程难度

1 个答案: