Question

我试图从mysql数据库中获取img URL并显示图像本身，而不是URL链接。

有没有办法将某些HTML连接到我在下面运行的php脚本中？

现在它显示图片网址很好但希望它显示它正在调用的实际图片。

<?php
            $db = new mysqli('localhost', 'root', 'root', 'testdb');

            if($db->connect_errno > 0){
                die('Unable to connect to database [' . $db->connect_error . ']');
            }

            $sql = <<<SQL
                SELECT *
                FROM `site_img`
            SQL;

            if(!$result = $db->query($sql)){
                die('There was an error running the query [' . $db->error . ']');
            }
            while($row = $result->fetch_assoc()){
                echo $row['img_id'] . ' ' . $row['img_url'] . '<br />';
            }
            echo 'Total results: ' . $result->num_rows;

            // Free result set
            mysqli_free_result($result);

            mysqli_close($db);
            ?>

Answer 1

您可以在循环中插入html img标记。

<?php
            $db = new mysqli('localhost', 'root', 'root', 'testdb');

            if($db->connect_errno > 0){
                die('Unable to connect to database [' . $db->connect_error . ']');
            }

            $sql = <<<SQL
                SELECT *
                FROM `site_img`
            SQL;

            if(!$result = $db->query($sql)){
                die('There was an error running the query [' . $db->error . ']');
            }
            while($row = $result->fetch_assoc()){
?>
            <img name="<?php echo $row['img_id'] ?>" src="<?php $row['img_url'] ?>" /> <br />
<?php
            }
            echo 'Total results: ' . $result->num_rows;

            // Free result set
            mysqli_free_result($result);

            mysqli_close($db);
?>

在PHP＆amp;中显示来自URL的img MySQL的

1 个答案: