Question

我正在向远程服务器发送请求，它正在发送纯文本JSON类型响应！我尝试在php变量中获取该响应并尝试使用json_decode，但它总是返回null值！

<?php

function removefunction($data){
checkagain:
$functionposition=stripos($data,"function()");
if($functionposition){
$subdata= substr($data, $functionposition);
$functiondata=substr($data, $functionposition,stripos($subdata,"}")+1);

$endoffunction=stripos($subdata,"}");
$endoffunction=$endoffunction+$functionposition;

$questionmarkpos=stripos($functiondata,'?"');
$colonpos=stripos($functiondata,'":"');
$realvalue=substr($functiondata, $questionmarkpos+2,$colonpos-$questionmarkpos-2);
$data=str_ireplace($functiondata,"\"$realvalue\"",$data);
goto checkagain;
}
return $data;
}

$json=<<<EOT
obj1431027525490 = { trains: [ { trainNo: "12392", startDate: "6 May 2015", trainName: "SHRAMJEEVI EXPRESS", trnName:function(){return _LANG=="en-us"?"SHRAMJEEVI EXPRESS":""}, divertedFrom: "NDLS", divertedTo: "GZB", trainSrc: "NDLS", trainDstn: "RGD", trainType: "SUPERFAST" }, { trainNo: "13162", startDate: "7 May 2015", trainName: "BLGT-KOLKATA EXP.", trnName:function(){return _LANG=="en-us"?"BLGT-KOLKATA EXP.":""}, divertedFrom: "NFK", divertedTo: "KOAA", trainSrc: "BLGT", trainDstn: "KOAA", trainType: "MAIL_EXP" }] }; 
EOT;
$json= substr($json, 19);
$json=substr_replace($json, "", -2);
echo $json."<br/><br/><br/>".PHP_EOL.PHP_EOL.PHP_EOL;
$json=removefunction($json);
$json = preg_replace('/(?<!")(?<!\w)(\w+)(?!")(?!\w)/', '"$1"', $json);
echo $json;
$contents = utf8_encode($json); 
$obj = json_decode($json,true);
var_dump($obj);

?>

问题：preg_replace在已引用的文本之间添加引用！

PS：这就是我想通过php数组http://i.imgur.com/4ZGEHAv.png

将数据打印到表中的方法

您可以在上面的屏幕截图中使用原始网站的Diverted Train响应！

Answer 1

我应该告诉你将json转换为php变量的基本语法。请记住，这是使用utf-8编码

//让这个例子清楚明白

$json = {"foo-bar" : 1234};

$obj = json_decode($json);

print $obj -> {'foo-bar'}; // 1234

如果你想把它作为php var

$var = $obj->{'foo-bar'}; // the values keep 1234

将json转换为php array assoc

如果你使用像json这样的

，你不能使用json来获取php var

$json = {'foo' : '1234'};  // return null
$json = {foo : 1234}; // Null
$json = {foo: "1234"};

该示例可能在javascript中有效，但在json中无效。

Answer 2

我能够通过以下修改来解析它：

删除了obj1431027525490 =
删除了最后的;
使用键trnName
用双引号括起所有键

工作示例：

<?php
$json=<<<EOT
{ "trains": [ { "trainNo": "12392", "startDate": "6 May 2015", "trainName": "SHRAMJEEVI EXPRESS", "divertedFrom": "NDLS", "divertedTo": "GZB", "trainSrc": "NDLS", "trainDstn": "RGD", "trainType": "SUPERFAST" }, { "trainNo": "13162", "startDate": "7 May 2015", "trainName": "BLGT-KOLKATA EXP.", "divertedFrom": "NFK", "divertedTo": "KOAA", "trainSrc": "BLGT", "trainDstn": "KOAA", "trainType": "MAIL_EXP" }] }
EOT;

$contents = utf8_encode($json); 
$obj = json_decode($contents,true);
var_dump($obj);

Answer 3

<?php

function removefunction($data){
    checkagain:
$functionposition=stripos($data,"function()");
    if($functionposition){
    $subdata= substr($data, $functionposition);
    $functiondata=substr($data, $functionposition,stripos($subdata,"}")+1);

    $endoffunction=stripos($subdata,"}");
    $endoffunction=$endoffunction+$functionposition;

    $questionmarkpos=stripos($functiondata,'?"');
    $colonpos=stripos($functiondata,'":"');
    $realvalue=substr($functiondata, $questionmarkpos+2,$colonpos-$questionmarkpos-2);
    $data=str_ireplace($functiondata," \"$realvalue\"",$data);
    goto checkagain;
    }
    return $data;
}
function json_fix_quotes ($string){
    //$string = str_replace("{",'{"',$string);
    $string = str_replace(":'",'":"',$string);
    $string = str_replace(': ','": ',$string);
    $string = str_replace(", ",', "',$string);
    $string = str_replace("',",'","',$string);
    $string= str_replace('{" ','{"',$string);
    $string= str_replace(', "{',', {',$string);
    $string = str_replace("{ ",'{"',$string);
    return $string;
}

$json=<<<EOT
obj1431027525490 = { trains: [ { trainNo: "12392", startDate: "6 May 2015", trainName: "SHRAMJEEVI EXPRESS", trnName:function(){return _LANG=="en-us"?"SHRAMJEEVI EXPRESS":""}, divertedFrom: "NDLS", divertedTo: "GZB", trainSrc: "NDLS", trainDstn: "RGD", trainType: "SUPERFAST" }, { trainNo: "13162", startDate: "7 May 2015", trainName: "BLGT-KOLKATA EXP.", trnName:function(){return _LANG=="en-us"?"BLGT-KOLKATA EXP.":""}, divertedFrom: "NFK", divertedTo: "KOAA", trainSrc: "BLGT", trainDstn: "KOAA", trainType: "MAIL_EXP" }] }; 
EOT;
$json= substr($json, 19);
$json=substr_replace($json, "", -2);
echo $json."<br/><br/><br/>".PHP_EOL.PHP_EOL.PHP_EOL;
$json=removefunction($json);
$json = json_fix_quotes($json);
echo $json;
$contents = utf8_encode($json); 
$obj = json_decode($json,true);
var_dump($obj);

?>

如何将此文本json响应转换为php数组

3 个答案: