如何将JSON数据（在PHP变量中）转换为Jquery数组？

Question

我尝试通过给出它的邮政编码来获取地址，并使用getaddress.io网站api和php，它给出了如下给出的JSON结果集，问题是在php变量 $ file 中的结果集。现在我必须将JSON结果转换为jquery数组。

{
"Latitude":-0.020223,
"Longitude":51.504859,
"Addresses":[
  "Abbey Offices Ltd, 1 Canada Square, LONDON",
  "B B V A, 1 Canada Square, LONDON",
  "B P R Interiors Ltd, 1 Canada Square, LONDON",
  "Citihub Ltd, 1 Canada Square, LONDON",
  "Coutts & Co, 1 Canada Square, LONDON",
  "Diligence Ltd, 1 Canada Square, LONDON",
  "Doctors of the World UK, 1 Canada Square, LONDON",
  "Doyle Clayton, 1 Canada Square, LONDON",
  ]
}    

我想要的输出作为jquery数组的值是，

var output= [
  "Abbey Offices Ltd, 1 Canada Square, LONDON",
  "B B V A, 1 Canada Square, LONDON",
  "B P R Interiors Ltd, 1 Canada Square, LONDON",
  "Citihub Ltd, 1 Canada Square, LONDON",
  "Coutts & Co, 1 Canada Square, LONDON",
  "Diligence Ltd, 1 Canada Square, LONDON",
  "Doctors of the World UK, 1 Canada Square, LONDON",
  "Doyle Clayton, 1 Canada Square, LONDON",
  ];

请帮我解决这个问题。 提前致谢

Answer 1

Per @Darren上述评论：

var data = {
"Latitude":-0.020223,
"Longitude":51.504859,
"Addresses":[
  "Abbey Offices Ltd, 1 Canada Square, LONDON",
  "B B V A, 1 Canada Square, LONDON",
  "B P R Interiors Ltd, 1 Canada Square, LONDON",
  "Citihub Ltd, 1 Canada Square, LONDON",
  "Coutts & Co, 1 Canada Square, LONDON",
  "Diligence Ltd, 1 Canada Square, LONDON",
  "Doctors of the World UK, 1 Canada Square, LONDON",
  "Doyle Clayton, 1 Canada Square, LONDON",
  ]
};
  
var output = data.Addresses;
alert(output);