Question

好的，我已经编写了这段代码并多次查看，看看能不能找到我的错误。不幸的是，我找不到它，我对自己感到沮丧。我决定在线发布我的代码。这是带有方法的实际Calculator类。输入类（不在此帖子上）获取用户输入并将其作为字符串返回。有人可以帮帮我吗？谢谢兄弟们。

public class Calculate extends UserInput{

int num1;
int num2;
int returnValue;
String operation;
String userInput1;
String userInput2;

public void calculate() {
    userInput1 = getUserInput("Enter a number: ");
    num1 = Integer.parseInt(userInput1); //Changing userInput to int
    operation = getUserInput("Enter an operation (+,-,*, or /): ");
    userInput2 = getUserInput("Enter a second number: "); //Changing second userInput to int
    num2 = Integer.parseInt(userInput2);

    if(operation == "+") {
        addition(num1, num2);
    } else if (operation == "-") {
        subtraction(num1, num2);
    } else if (operation == "*") {
        multiplication(num1, num2);
    } else if (operation == "/") {
        division(num1, num2);
    }

    System.out.println("Result: " + returnValue);
}

public double addition(int x, int y) {
    returnValue = x + y;
    return returnValue;
}

public double subtraction(int x, int y) {
    returnValue = x - y;
    return returnValue;
}

public double multiplication(int x, int y) {
    returnValue = x * y;
    return returnValue;
}

public double division(int x, int y) {
    returnValue = x / y;
    return returnValue;
}

}

Answer 1

这是我解决问题的方法！谢谢社区！

    if(operation .equals("+")) {
        returnValue = addition(num1, num2);
    } else if (operation .equals("-")) {
        returnValue = subtraction(num1, num2);
    } else if (operation .equals("*")) {
        returnValue = multiplication(num1, num2);
    } else if (operation .equals("/")) {
        returnValue = division(num1, num2);
    }

Answer 2

if(operation.equals("+")) {
    addition(num1, num2);
} else if (operation.equals("-")) {
    subtraction(num1, num2);
} else if (operation.equals("*")) {
    multiplication(num1, num2);
} else if (operation.equals("/")) {
    division(num1, num2);
}

计算器程序通过答案得出结果＆＃34; 0＆＃34;？

2 个答案: