谁能告诉我为什么这个结果一直为0？ （C程序）

Question

    case 2:
        if(hrswrk <= 40)
            pay = wage * hrswrk;
        else
            pay = (40 * wage) + (hrswrk - 40) * (wage * 1.5);
        printf("Hourly Workers is selected. \n");
        printf("Enter number of hours worked: \n");
        scanf("%i",&hrswrk);
        printf("Enter hourly wage: \n");
        scanf("%i",&wage);
        printf("Your pay is Php%.2f",pay);
        break;

这只是我程序的一部分，令人沮丧的是我什至无法解决它，也许错误是我在开关中放置了if else语句？我很迷路。

Answer 1

在获取所需数据后进行操作：

case 2:
    printf("Hourly Workers is selected. \n");
    printf("Enter number of hours worked: \n");
    scanf("%i",&hrswrk);
    printf("Enter hourly wage: \n");
    scanf("%i",&wage);

    if(hrswrk <= 40)
        pay = wage * hrswrk;
    else
        pay = (40 * wage) + (hrswrk - 40) * (wage * 1.5);

    printf("Your pay is Php%.2f",pay);
    break;

Answer 2

在建立pay和hrswrk的值之后，需要计算wage ，即，移动if块在最后一次scanf通话之后。

尽管某些语言以您编写的方式工作，但C却没有。

还请注意，您应始终检查scanf的返回值，以检查读取是否成功。

Answer 3

在if-condition之后执行scanf()

在您的代码中，您正在执行if-condition，然后再读取hrswrk和wage。首先阅读它们并执行if-logic。

尝试此修改后的代码：-

case 2:
    printf("Hourly Workers is selected. \n");
    printf("Enter number of hours worked: \n");
    scanf("%i", &hrswrk);
    printf("Enter hourly wage: \n");
    scanf("%i", &wage); 

    if (hrswrk <= 40)   // if condition after scanning wage and  hrswrk
        pay = wage * hrswrk;
    else
        pay = (40 * wage) + (hrswrk - 40) * (wage * 1.5);
    printf("Your pay is Php%.2f", pay);
    break;

这将起作用。

Answer 4

 case 2:
        printf("Hourly Workers is selected. \n");
        printf("Enter number of hours worked: \n");
        scanf("%i",&hrswrk);
        printf("Enter hourly wage: \n");
        scanf("%i",&wage);
       if(hrswrk <= 40)
            pay = wage * hrswrk;
        else
            pay = (40 * wage) + (hrswrk - 40) * (wage * 1.5);
        printf("Your pay is Php%.2f",pay);
        break;