Question

我是新的，标准的开始，所以我会把剩下的都留下来。我是否必须将每个int转换为秒，或者这是对的吗？因为当我向后计算，手动并计算最终语句的秒数时，我会得到几小时的差异。

Thx Casu

    Scanner input = new Scanner(System.in);
    final int secmin = 60;
    final int day = 24;
    final int year = 365;
    int seconds = input.nextInt();
    int minutes = seconds / secmin;
    int remainSec = seconds % secmin ;

    int hours = minutes / secmin;
    int remainMin = hours % secmin;
    int days = hours / day;
    int remainHours = hours % day;
    int years = days / year;
    int remainDays = days % year;

    if (minutes <= 59)
    {
        System.out.println(seconds + " seconds is " + minutes +" minutes and " + remainSec + " seconds");
    }
    else if (hours <= 23) 
    {   

        System.out.println(seconds + " seconds is " + hours +" hours and " + remainMin + " minutes " + remainSec + " seconds");
    }
    else if (days <= 364)
    {   

        System.out.println(seconds + " seconds is " + days + " days "  + remainHours +" hours and " + remainMin + " minutes " + remainSec + " seconds");
    }

    else
    {
        System.out.println(seconds + " seconds is " + years + " years " + remainDays + " days "  + remainHours +" hours and " + remainMin + " minutes " + remainSec + " seconds");
    }

Answer 1

我认为这个陈述需要改变：来自＆＃34; int remainingMin =小时％sec min;＆＃34;

到＆＃34; int remainingMin =分钟％secmin;＆＃34;。

休息一下看起来不错。

Answer 2

代码看起来不错。但是，我会删除＆＃34; Magic Numbers＆＃34;来自if语句：

Scanner input = new Scanner(System.in);
final int secmin = 60;
final int day = 24;
final int year = 365;
int seconds = input.nextInt();
int minutes = seconds / secmin;
int remainSec = seconds % secmin ;

int hours = minutes / secmin;
int remainMin = hours % secmin;
int days = hours / day;
int remainHours = hours % day;
int years = days / year;
int remainDays = days % year;

if (minutes < secMin)
{
    System.out.println(seconds + " seconds is " + minutes +" minutes and " + remainSec + " seconds");
}
else if (hours < day) 
{   

    System.out.println(seconds + " seconds is " + hours +" hours and " + remainMin + " minutes " + remainSec + " seconds");
}
else if (days < year)
{   

    System.out.println(seconds + " seconds is " + days + " days "  + remainHours +" hours and " + remainMin + " minutes " + remainSec + " seconds");
}

else
{
    System.out.println(seconds + " seconds is " + years + " years " + remainDays + " days "  + remainHours +" hours and " + remainMin + " minutes " + remainSec + " seconds");
}

我知道年/日/小时/分钟/秒的比例都是非常静态的，但是如果有人想要在10秒到10分钟到10小时之间看到你的代码呢？然后你只需要换一个地方而不是两个。

在生产应用程序中，这可能会增长到代码中的数百个位置，并且很难追逐每一个位置。

Answer 3

我确实输了=

1234234234 s

输出=

1234234234秒是39年50天2小时2分34秒

和=

1229904000 s + 4320000 s + 7200 s + 120 s + 34 s = 1234231354 s

差异=

2880 s

当我改变时：

int remainingMin =小时％secmin; “to”int remainingMin = minutes％secmin;

然后：

1234234234秒是39年50天2小时50分34秒

结果：

48分钟添加

1229904000 s + 4320000 s + 7200 s + 3000 s + 34 s = 1234234234 s

，差异为0。

感谢您更正用户2006544和改进史蒂夫。

将秒转换为Year Hour Minutes Seconds

3 个答案: