Question

我对.Net Json序列化有点问题我有类列表的类，我需要将它序列化为属性，例如：

原：

class:
kid{
   int age;
   String name;
   List[String] toys;
}

结果：

{
    "age":10,
    "name": Jane,
    "toys":["one", "two", "three"]
}

我需要

{
    "age":10,
    "name": Jane,
    "toy_1": "one", 
    "toy_2": "two",
    "toy_3": "three"  
}

这是因为api。有什么方法可以做到吗？

Answer 1

这是一个不假设玩具数量的动态解决方案：

    public class kid
    {
        public int age;
        public String name;
        public List<String> toys;

        public string ApiCustomView
        {
            get
            {
                Dictionary<string, string> result = new Dictionary<string, string>();
                result.Add("age", age.ToString());
                result.Add("name", name);
                for (int ii = 0; ii < toys.Count; ii++)
                {
                    result.Add(string.Format("toy_{0}", ii), toys[ii]);
                }
                return result.ToJSON();
            }
        }
    }

用法：

    static void Main(string[] args)
    {
        var k = new kid { age = 23, name = "Paolo", toys = new List<string>() };
        k.toys.Add("Pippo");
        k.toys.Add("Pluto");

        Console.WriteLine(k.ApiCustomView);
        Console.ReadLine();
    }

它使用您可以在此处找到的扩展程序：How to create JSON string in C#

namespace ExtensionMethods
{
    public static class JSONHelper
    {
        public static string ToJSON(this object obj)
        {
            JavaScriptSerializer serializer = new JavaScriptSerializer();
            return serializer.Serialize(obj);
        }

        public static string ToJSON(this object obj, int recursionDepth)
        {
            JavaScriptSerializer serializer = new JavaScriptSerializer();
            serializer.RecursionLimit = recursionDepth;
            return serializer.Serialize(obj);
        }
    }
}

Answer 2

正如dcastro所说，它是一个奇怪的API，你应该改变它，如果你能接受一个数组。如果你不能，你可以尝试创建和匿名类型，所以你会有类似的东西：

public object GetSerializationObjectForKid(Kid kid)
{
    return new 
    {
        age = kid.age,
        name = kid.name,
        toy_1 = toys.ElementAtOrDefault(0), 
        toy_2 = toys.ElementAtOrDefault(1),
        toy_3 = toys.ElementAtOrDefault(2)
    }
}

您可以序列化这个新的匿名对象。

Answer 3

以下是使用Anonymous Type选择成员并为其命名以符合api要求的示例。它目前假设总会有3＆＃34;玩具＆＃34;。

using System.Linq;
using System;
using System.Collections.Generic;
using System.Text;
using System.Xml;
using System.Web.Script.Serialization;
namespace CommandLineProgram
{
    public class DefaultProgram
    {
        public static void Main()
        {
            var kid1 = new kid() 
            { 
                age = 10, 
                name = "Jane", 
                toys = new List<String> 
                { 
                    "one", 
                    "two", 
                    "three" 
                } 
            };

            var asdf = new
            {
                age = kid1.age,
                name = kid1.name,
                toy_1 = kid1.toys[0],
                toy_2 = kid1.toys[1],
                toy_3 = kid1.toys[2]
            };

            JavaScriptSerializer ser = new JavaScriptSerializer();

            String serialized = ser.Serialize(asdf);
            Console.WriteLine(serialized);
        }
    }

    public class kid
    {
        public int age;
        public String name;
        public List<String> toys;
    }
}

生成此输出

{
  "age" : 10,
  "name" : "Jane",
  "toy_1" : "one",
  "toy_2" : "two",
  "toy_3" : "three"
}

Answer 4

您可以构建一个动态对象，添加所需的属性，然后将其序列化

dynamic jsonData = new System.Dynamic.ExpandoObject();
jsonData.age = kid.age;
jsonData.name = kid.name;
for (int i = 0; i < kid.toys.Count; i++)
        {
            ((IDictionary<String, Object>)jsonData).Add(string.Format("toy_{0}", i), kid.toys[i]);
        }

C＃Json序列化列表

4 个答案: