Question

我的对象是这样实现的：

class TestLog:
    def __init__(self):
        self.test_name = "Unknown"
        self.test_package = "Unknown"
        self.test_status = "Unknown"
        self.device = "Unknown"
        self.test_start_time = -1
        self.test_end_time = -1
        self.ran_times = 1
        self.error_messages = list()

    def __dict__(self):
        test_log_dict = dict()
        test_log_dict["test_name"] = self.test_name
        test_log_dict["test_package"] = self.test_package
        test_log_dict["test_status"] = self.test_status
        test_log_dict["device"] = self.device
        test_log_dict["test_start_time"] = self.test_start_time
        test_log_dict["test_end_time"] = self.test_end_time
        test_log_dict["ran_times"] = self.ran_times
        test_log_dict["error_messages"] = self.error_messages
        return test_log_dict

我可以把它变成JSON：

import json

log1 = TestLog()
log2 = TestLog()
json_dump1 = json.dumps(log1.__dict__())
json_dump2 = json.dumps(log2.__dict__())

输出是 - 2个独立的json对象：

LOG1：

{
    "test_name": "Unknown",
    "test_package": "Unknown",
    "test_status": "Unknown",
    "device": "Unknown",
    "test_start_time": -1,
    "test_end_time": -1,
    "ran_times": 1,
    "error_messages": []
}

的log 2：

{
    "test_name": "Unknown",
    "test_package": "Unknown",
    "test_status": "Unknown",
    "device": "Unknown",
    "test_start_time": -1,
    "test_end_time": -1,
    "ran_times": 1,
    "error_messages": []
}

我想知道这个结果：

{
    "test_results": [
        {
            "test_name": "Unknown",
            "test_package": "Unknown",
            "test_status": "Unknown",
            "device": "Unknown",
            "test_start_time": -1,
            "test_end_time": -1,
            "ran_times": 1,
            "error_messages": []
        },
        {
            "test_name": "Unknown",
            "test_package": "Unknown",
            "test_status": "Unknown",
            "device": "Unknown",
            "test_start_time": -1,
            "test_end_time": -1,
            "ran_times": 1,
            "error_messages": []
        }
    ]
}

但这种方法对我不起作用：

    log_dict = dict()
    log_dict.update({"test_results": [json_dump1, json_dump2]})
    list_dump = json.dumps(log_dict)

因为这种情况发生了：

{＆＃34; test_results＆＃34;：[＆＃34; {\＆＃34; test_name \＆＃34;：\＆＃34; Unknown \＆＃34;，\＆＃34; test_package \ ＆＃34;：\＆＃34;未知\＆＃34;，\＆＃34; test_status \＆＃34;：\＆＃34;未知\＆＃34;，\＆＃34;设备\＆＃ 34;：\＆＃34; Unknown \＆＃34;，\＆＃34; test_start_time \＆＃34;：-1，\＆＃34; test_end_time \＆＃34;：-1，\＆＃34; ran_times \＆＃34;：1，\＆＃34; error_messages \＆＃34;：[]}＆＃34;，＆＃34; {\＆＃34; test_name \＆＃34;：\＆＃34 ;未知\＆＃34;，\＆＃34; test_package \＆＃34;：\＆＃34;未知\＆＃34;，\＆＃34; test_status \＆＃34;：\＆＃34;未知\＆＃34;，\＆＃34;设备\＆＃34;：\＆＃34;未知\＆＃34;，\＆＃34; test_start_time \＆＃34;：-1，\＆＃34; test_end_time \＆＃34;：-1，\＆＃34; ran_times \＆＃34;：1，\＆＃34; error_messages \＆＃34;：[]}＆＃34;]}

Answer 1

json.dumps返回一个字符串，因此您实际上是将字符串附加到log_dict['test_results']。

相反，将整个字典作为一个整体创建，然后一次性将其转换为json字符串：

log_dict = dict()
log_dict.update({"test_results": [log1.__dict__(), log2.__dict__()]})
list_dump = json.dumps(log_dict)
print(list_dump)

# {
#       "test_results": [{
#       "device": "Unknown",
#       "error_messages": [],
#       "test_status": "Unknown",
#       "test_start_time": -1,
#       "ran_times": 1,
#       "test_package": "Unknown",
#       "test_name": "Unknown",
#       "test_end_time": -1
#   }, {
#       "device": "Unknown",
#       "error_messages": [],
#       "test_status": "Unknown",
#       "test_start_time": -1,
#       "ran_times": 1,
#       "test_package": "Unknown",
#       "test_name": "Unknown",
#       "test_end_time": -1
#   }]
# }

顺便说一下，如果你想要实现的话，你甚至不需要实现__dict__。默认的__dict__方法已经为您完成，可以通过调用对象上的vars来调用：

import json

class TestLog:
    def __init__(self):
        self.test_name = "Unknown"
        self.test_package = "Unknown"
        self.test_status = "Unknown"
        self.device = "Unknown"
        self.test_start_time = -1
        self.test_end_time = -1
        self.ran_times = 1
        self.error_messages = list()


log1 = TestLog()
log2 = TestLog()


log_dict = dict()
log_dict.update({"test_results": [vars(log1), vars(log2)]})
list_dump = json.dumps(log_dict)

print(list_dump)

# {
#       "test_results": [{
#       "device": "Unknown",
#       "error_messages": [],
#       "test_status": "Unknown",
#       "test_start_time": -1,
#       "ran_times": 1,
#       "test_package": "Unknown",
#       "test_name": "Unknown",
#       "test_end_time": -1
#   }, {
#       "device": "Unknown",
#       "error_messages": [],
#       "test_status": "Unknown",
#       "test_start_time": -1,
#       "ran_times": 1,
#       "test_package": "Unknown",
#       "test_name": "Unknown",
#       "test_end_time": -1
#   }]
# }

使用更简单的类定义实现了相同的结果。

Answer 2

当然，因为你需要一个字典作为值，但是你要存储代表序列化字典的json字符串。

我会这样做：

log_dict = {"test_results": [log1.__dict__(), log2.__dict__()]})

如果之前必须冻结log1和log2，请复制该词组

log1_dict = log1.__dict__().copy()
log2_dict = log2.__dict__().copy()

然后：

log_dict = {"test_results": [log1_dict, log2_dict]})

将对象列表序列化为json数组列表

2 个答案: