我遇到了问题,我无法处理带有预处理语句的重复条目。
我想在出现重复条目时结束程序。这就是我一直在努力做的事情:
function insert_vulnerability ($CVE, $Description, $Date, $Score, $Type){
$conn = connection();
$stmt = $conn->prepare("INSERT INTO Vulnerabilities (CVE, Description, Date, Score, Type)
VALUES (?, ?, ?, ?, ?)");
$stmt->bind_param("sssis", $CVE, $Description, $Date, $Score, $Type);
if ( false === $stmt ) {
die('prepare() failed: ' . htmlspecialchars($mysqli->error));
}
$stmt->execute();
$conn->close();
}
当不使用准备好的语句时,我以这种方式处理错误,一切都运行良好:
function insert_vulnerability ($CVE, $Description, $Date, $Score, $Type){
$conn = connection();
$Description = htmlspecialchars($Description);
$sql = "INSERT INTO Vulnerabilities (CVE, Description, Date, Score, Type)
VALUES ('".$CVE."', '".$Description."', '".$Date."', '".$Score."', '".$Type."')";
if ($conn->query($sql) === TRUE) {
//echo "New record created successfully";
} else {
echo "Error: " . $sql . "<br>" . $conn->error;
$conn->close();
die();
}
$conn->close();
}
那么如何用准备好的陈述得到相同的结果?
提前谢谢。
答案 0 :(得分:1)
您可以连接$stmt->execute()
内的检查,看看准备好的语句是否正常工作。
function insert_vulnerability ($CVE, $Description, $Date, $Score, $Type){
$conn = connection();
$stmt = $conn->prepare('
INSERT INTO Vulnerabilities (CVE, Description, Date, Score, Type)
VALUES (?, ?, ?, ?, ?)
');
$stmt->bind_param('sssis', $CVE, $Description, $Date, $Score, $Type);
if($stmt->execute()) { // true, success, else error
echo 'New record created successfully';
} else {
echo $conn->error;
}
$conn->close();
}
请注意,您准备好的声明方面有一个未定义的变量:
$mysqli->error