Question

我在matlab中编写了一个井字游戏，但它不起作用：

%// 1) Commence the game, display empty board 

board=cell(3);

%// 2) Select which player is ?X? and ?O? (at random) 

playersymbols={'X','O'};
playersymbolindex=randperm(2);
for i=1:2
    player(i).symbol=playersymbols{playersymbolindex(i)};
end

winner=0;

while winner<1 
    %// 3) Request player1?s move

    player1move=input('Player 1, please enter your move: ');

    %// the input is something like [1 3] where the first number is the
    %// row number and the second number is column number so that [1 3] will
    %// put X in row 1, column 3.

    %// Redraw updated board. 
    board{player1move(1),player1move(2)}=player(1).symbol;
    board



    %// 5) Decision: has the game been won yet? If so, go to step 9).
    %//    If not, go to step 6). 

    %// The game is won when three respective X are placed in a horizontal,
    %// vertical, or diagonal row.

    if board{1,1}==board{1,2} & board {1,2}==board{1,3} | ...
       board{2,1}==board{2,2} & board{2,2}==board{2,3} | ...
       board{3,1}==board{3,2} & board{3,2}==board{3,3} | ...
       board{1,1}==board{2,1} & board{2,1}==board{3,1} | ...
       board{1,2}==board{2,2} & board{2,2}==board{3,2} | ...
       board{1,3}==board{2,3} & board{2,3}==board{3,3} | ...
       board{1,1}==board{2,2} & board{2,2}==board{3,3} | ...
       board{1,3}==board{2,2} & board{2,2}==board{3,1}

        %// 9) Display winner on the screen. 

        disp('Winner is player 1!')

        winner=1; 
    else

        %// 6) Request player2?s move 

        player2move=input('Player 2, please enter your move: ');

        %// 7) Input Player2?s move. Redraw updated board.

        board{player2move(1),player2move(2)}=player(2).symbol;
        board


        %// 8) Decision: has the game been won yet? If so, go to step 9). 
        %//    If not, go back to step 3). 

        if board{1,1}==board{1,2} & board {1,2}==board{1,3} | ...
           board{2,1}==board{2,2} & board{2,2}==board{2,3} | ...
           board{3,1}==board{3,2} & board{3,2}==board{3,3} | ...
           board{1,1}==board{2,1} & board{2,1}==board{3,1} | ...
           board{1,2}==board{2,2} & board{2,2}==board{3,2} | ...
           board{1,3}==board{2,3} & board{2,3}==board{3,3} | ...
           board{1,1}==board{2,2} & board{2,2}==board{3,3} | ...
           board{1,3}==board{2,2} & board{2,2}==board{3,1}

           %// 9) Display winner on the screen. 

           disp('Winner is player 2!')
           winner=1;
        end
    end
end

我非常努力地理解我做错了什么，但是4小时后，我无能为力。有人可以帮帮我吗？我做错了什么？

编辑：播放器1正常，因此问题在于播放器2.当播放器2获胜时，我的程序不显示“播放器2赢得了游戏”并错误地要求播放器1接下来移动（游戏已经完成）。

Answer 1

我发现了这个问题。

当您将字符串与==而非strcmp进行比较时，如果存在空字符串，则比较将返回[]。因此TRUE | []的逻辑运算符返回[]，这不是真的。

在您发布的示例中（[1 1]，[1 2]，[2 1]，[2 2]，[1 3]，[3 2]）if的最后一行返回[]

board{1,3}==board{2,2} & board{2,2}==board{3,1}

如果您用&&和||替换逻辑运算符，就可以解决问题。

Answer 2

我同意Steffen，我也会将比较作为一个单独的功能。这是一个实现：

%// 1) Commence the game, display empty board 

board=cell(3);

%// 2) Select which player is ?X? and ?O? (at random) 

playersymbols={'X','O'};
playersymbolindex=randperm(2);
for i=1:2
    player(i).symbol=playersymbols{playersymbolindex(i)};
end

winner=0;

while winner<1 
    %// 3) Request player1?s move

    player1move=input('Player 1, please enter your move: ');

    %// the input is something like [1 3] where the first number is the
    %// row number and the second number is column number so that [1 3] will
    %// put X in row 1, column 3.

    %// Redraw updated board. 
    board{player1move(1),player1move(2)}=player(1).symbol;
    board



    %// 5) Decision: has the game been won yet? If so, go to step 9).
    %//    If not, go to step 6). 

    %// The game is won when three respective X are placed in a horizontal,
    %// vertical, or diagonal row.

    if gameWon(board, player(1).symbol)

        %// 9) Display winner on the screen. 

        disp('Winner is player 1!')

        winner=1; 
    else

        %// 6) Request player2?s move 

        player2move=input('Player 2, please enter your move: ');

        %// 7) Input Player2?s move. Redraw updated board.

        board{player2move(1),player2move(2)}=player(2).symbol;
        board


        %// 8) Decision: has the game been won yet? If so, go to step 9). 
        %//    If not, go back to step 3). 

        if gameWon(board, player(2).symbol)

           %// 9) Display winner on the screen. 

           disp('Winner is player 2!')
           winner=1;
        end
    end
end

功能gameWon：

function result = gameWon(board, playersymbol)
    result = (isequal(board{1,1},board{1,2},playersymbol) && isequal(board{1,1},board{1,3},playersymbol)) || ...
             %// repeat for all your cases
end

Answer 3

这是真实的行为。

如果第一个语句是1，则if子句会起作用。

您应该使用一些默认值来初始化您的电路板 - ＆＃39; - ＆＃39;。然后使用运算符＆amp;＆amp;和||而不是＆amp;和|。然后你还需要检查实际玩家的正确符号。

Answer 4

＆安培;和|是按元素进行逻辑比较，如果在内容为空的单元格上使用它们，则结果为0x0矩阵。

然后将得到的0x0矩阵与其他东西进行比较，其他东西也可能是0x0 matrizes或逻辑TRUE或逻辑FALSE。在任何情况下，程序都不会在if条件下执行您认为的操作。

解决这个问题的最简单方法是替换|通过||和＆amp; by＆amp;＆amp;，因为后两者总是返回逻辑FALSE或TRUE。

我在matlab中的tic-tac-toe程序不起作用

4 个答案: