Question

我尝试创建一个正则表达式来提取电话，街道地址，页面值（9440717256，H.No.3-11-62 ，RTC Colony ..）来自python中的html页面。这三个字段是可选的我尝试了这个正则表达式，但输出不一致

telephone\S+>(.+)</em>.*(?:streetAddress\S+(.+)</span>)?.*(?:pages\S+>(.+)</a></span>)?

示例字符串

<em phone="**telephone**">9440717256</em></div></div></li><li class="row"><i class="icon-sm icon-address"></i><div class="profile-details"><strong>Address</strong><div class="profi`enter code here`le-child"><address itemprop="address" itemscope="" itemtype="http://schema.org/PostalAddress" class="data-item"><span itemprop="**streetAddress**">H.No. 3-11-62, RTC Colony</span>, <span>Vastu Colony, </span><span class="text-black" itemprop="addressLocality"><a href="/hyderabad/lal-bahadur-nagar/allcategory.aspx" title="**Pages**">Lal Bahadur Nagar</a></span>

有人可以帮我建立正则表达式吗？

Answer 1

考虑到您的输入无效HTML 并且可能会有所变化，您可以使用像BeautifulSoup这样的HTML解析器。但如果您的输入发生变化，则必须调整这些简单的选择器。

from bs4 import BeautifulSoup

h = """<em phone="**telephone**">9440717256</em></div></div></li><li class="row"><i class="icon-sm icon-address"></i><div class="profile-details"><strong>Address</strong><div class="profi`enter code here`le-child"><address itemprop="address" itemscope="" itemtype="http://schema.org/PostalAddress" class="data-item"><span itemprop="**streetAddress**">H.No. 3-11-62, RTC Colony</span>, <span>Vastu Colony, </span><span class="text-black" itemprop="addressLocality"><a href="/hyderabad/lal-bahadur-nagar/allcategory.aspx" title="**Pages**">Lal Bahadur Nagar</a></span>"""
soup = BeautifulSoup(h)

修改：由于您现在告诉我们您需要具有指定属性值的元素的文本，因此您可以{{ 3}}

def find_phone(tag):
    return tag.has_attr("phone") and tag.get("phone") == "**telephone**"

def find_streetAddress(tag):
    return tag.has_attr("itemprop") and tag.get("itemprop") == "**streetAddress**"

def find_pages(tag):
    return tag.has_attr("title") and tag.get("title") == "**Pages**"


print(soup.find(find_phone).string)
print(soup.find(find_streetAddress).string)
print(soup.find(find_pages).string)

输出：

9440717256
H.No. 3-11-62, RTC Colony
Lal Bahadur Nagar

Answer 2

如果您了解HTML提供程序，内部代码看起来像什么，可以使用正则表达式。

然后，只使用替换和命名捕获组。

telephone[^>]*>(?P<Telephone>[^<]+)|streetAddress[^>]*>(?P<Address>[^<]+)|Pages[^>]*>(?P<Pages>[^<]+)

请参阅demo

如果>未序列化，您可以使用此正则表达式（更通用的一个，编辑：现在，详细）：

telephone[^<]*>        # Looking for telephone
  (?P<Telephone>[^<]+) # Capture telephone (all text up to the next tag)
|
streetAddress[^<]*>    # Looking for streetAddress
  (?P<Address>[^<]+)   # Capture address (all text up to the next tag)
|
Pages[^<]*>            # Looking for Pages
  (?P<Pages>[^<]+)     # Capture Pages (all text up to the next tag)

Sample demo on IDEONE

粘贴正则表达式代码部分：

p = re.compile(ur'''telephone[^<]*>        # Looking for telephone
  (?P<Telephone>[^<]+) # Capture telephone (all text up to the next tag)
|
streetAddress[^<]*>    # Looking for streetAddress
  (?P<Address>[^<]+)   # Capture address (all text up to the next tag)
|
Pages[^<]*>            # Looking for Pages
  (?P<Pages>[^<]+)     # Capture Pages (all text up to the next tag)''', re.IGNORECASE | re.VERBOSE)
test_str = "YOUR STRING"
print filter(None, [x.group("Telephone") for x in re.finditer(p, test_str)])
print filter(None, [x.group("Address") for x in re.finditer(p, test_str)])
print filter(None, [x.group("Pages") for x in re.finditer(p, test_str)])

输出（加倍的结果是我用不同的节点顺序复制输入字符串的结果）：

[u'9440717256', u'9440717256']
[u'H.No. 3-11-62, RTC Colony', u'H.No. 3-11-62, RTC Colony']
[u'Lal Bahadur Nagar', u'Lal Bahadur Nagar']

python中的可选单词正则表达式

2 个答案: