通过像素反转灰度图像像素

Question

我正在尝试编写一个C程序，它采用.raw灰度图像并逐像素地反转它。

我将每个像素存储在1D char数组中，然后将每个像素写入输出文件，只是顺序相反。

如果我尝试重现图像，我的程序会工作，但如果我尝试修改数组的索引，我会生成一个不可读的文件。

重现原始

#include <stdio.h>
#include <stdlib.h>

int main()
{
    FILE *fin, *fout;
    char ipath[64], opath[64], *rev, px;
    int i, row, read, width, height;

    printf("Name of input file: ");
    scanf("%s", ipath);
    printf("Name of output file: ");
    scanf("%s", opath);

    printf("Width of image: ");
    scanf("%d", &width);
    printf("Height of image: ");
    scanf("%d", &height);

    fin = fopen(ipath, "rb");
    fout = fopen(opath, "wb");

    rev = (char *)malloc(width * sizeof(char));

    row = 0;
    while(row < height)
    {
        for(i = 0; i < width; i++)
        {
            read = fread(&px, sizeof(char), 1, fin);
            rev[i] = px;
        }

        for(i = 0; i < width; i++)
            if(i < width && row < height)
                fwrite(&rev[i], sizeof(char), 1, fout);

        row++;
    }

    fclose(fout);
    fclose(fin);

    return 0;
}

反转图片

#include <stdio.h>
#include <stdlib.h>

int main()
{
    FILE *fin, *fout;
    char ipath[64], opath[64], *rev, px;
    int i, row, read, width, height;

    printf("Name of input file: ");
    scanf("%s", ipath);
    printf("Name of output file: ");
    scanf("%s", opath);

    printf("Width of image: ");
    scanf("%d", &width);
    printf("Height of image: ");
    scanf("%d", &height);

    fin = fopen(ipath, "rb");
    fout = fopen(opath, "wb");

    rev = (char *)malloc(width * sizeof(char));

    row = 0;
    while(row < height)
    {
        for(i = 0; i < width; i++)
        {
            read = fread(&px, sizeof(char), 1, fin);
            rev[width - 1 - i] = px;
        }

        for(i = 0; i < width; i++)
            if(i < width && row < height)
                fwrite(&rev[i], sizeof(char), 1, fout);

        row++;
    }

    fclose(fout);
    fclose(fin);

    return 0;
}

出于测试目的，我刚刚使用scanf()，但我知道它的问题。