魔方码

Question

#include <iostream>
#include <stdlib.h>
#include <time.h>
using namespace std;

// Functions used in the program.
bool uniqueCheck(int arr[][3], int num);
bool magicSquare(int arr[][3]);
int rTotal(int arr[][3], int row);
int cTotal(int arr[][3], int col);
int dTotal(int arr[][3], bool left);
void display(int arr[][3]);

int main()
{
    int arr[3][3]; //makes the array 3x3 makes it into the square
    int test[3][3] = {2, 7, 6, 9, 5, 1 , 4 , 3 ,8}; //numbers from 1-9 in order of magic square.

    while (1)
    {
        for (int i = 0; i < 3; i++)
            for (int j = 0; j < 3; j++)
                arr[i][j] = 0;// nested for loop the i is for rows and the j is for columns

        srand((unsigned)time(NULL));// generates random numbers
        for (int i = 0; i < 3; i++)
        {
            for (int j = 0; j < 3; j++)
            {
                while (1)
                {
                    int num = (rand() % 9) + 1; // Random function will spit out random numbers from 1-9.
                    if (uniqueCheck(arr, num))
                    {
                        arr[i][j] = num;
                        break;
                    }
                }
            }
        }

        display(arr);
        if (magicSquare(arr))//If the magic square array is an actual magic square than this outputs
        {
            cout << "This is the Magic Square !" << endl;
            break;
        }
        else //if not than it'll keep looping this until the top one is displayed
            cout << "This is Not the Magic Square !" << endl;

    }
    return 0;
}

// check if the random number generated is a unique number
bool uniqueCheck(int arr[][3], int num)
{
    for (int k = 0; k < 3; k++)
        for (int i = 0; i < 3; i++)
            if (arr[k][i] == num)
                return false;
    return true;
}

bool magicSquare(int arr[][3]) //This will check if the number presented (randomly) correspond with the magic square numbers.
{
    int sum = dTotal(arr, true); // Will check the sum of the diagonal.

    if (sum != dTotal(arr, false))
        return false;

    for (int i = 0; i < 3; i++)
    {
        if (sum != rTotal(arr, i)) // This will check each row and see if its true or false.
            return false;

        if (sum != cTotal(arr, i)) // This will check each column and see if its true or false.
            return false;
    }

    return true;
}

int rTotal(int arr[][3], int row) // This will calculate the sum of one row at a time.
{
    int sum = 0;
    for (int i = 0; i < 3; i++)
        sum += arr[row][i];
    return sum;
}

int cTotal(int arr[][3], int col) // This will calculate the sum of one column at a time.
{
    int sum = 0;
    for (int i = 0; i < 3; i++)
        sum += arr[i][col];
    return sum;
}

int dTotal(int arr[][3], bool left) // This will calculate the sum of diagonal. if the left is true, it will calculate from the left to the right diagonal. If false it will calculate from the right to the left diagonal.
{
    int sum = 0;
    if (left == true)
    {
        for (int i = 0; i < 3; i++)
            sum += arr[i][i];
        return sum;
    }

    for (int i = 0; i < 3; i++)
        sum += arr[i][3 - i - 1];
    return sum;
}

void display(int arr[][3]) //This will display the array.
{
    for (int i = 0; i < 3; i++)
    {
        for (int j = 0; j < 3; j++)
            cout << arr[i][j] << " ";
        cout << endl;
    }
    cout << endl;
}

这是我的代码。这计算出一个魔方。我唯一不能得到的是我的数字假设每次循环都会切换，但每次循环时显示相同的数字，这基本上使它成为一个无限循环...我要求的是帮助获取数字到每次循环时改变。非常感谢你提前。

Answer 1

在编写代码时，您应该在将其与其他代码集成之前单独开发新功能。

当你使用随机数生成器时，你应该注意到这一点：

srand((unsigned)time(NULL));// generates random numbers

重置随机数生成器。因为你在每次通过主循环时都这样做，所以每次都会得到相同的“随机”数字。

在循环外移动该行。