Question

我在Oracle表中有三百万个数据，分为三列，即时间戳，状态和值。

从temp_table rownum＆lt;中选择Rownum，Timestamp，Status，OrderId 11; 返回

1 2015-04-28T12：41：34.1616834Z预订100
2 2015-04-28T12：41：34.1888649Z删除100
3 2015-04-28T12：55：59.3789387Z执行200
4 2015-04-28T12：55：59.3825833Z坚持200
5 2015-04-28T12：55：59.3898336Z书200
6 2015-04-28T12：55：59.3903645Z删除200
7 2015-04-28T12：57：37.5718992Z预订200
8 2015-04-28T12：57：37.5723847Z删除200
9 2015-04-28T12：57：37.5725199Z预订300
10 2015-04-28T12：57：37.5728888Z删除300

我感兴趣的是对于那天的每个orderId，按执行，持久，预订和删除分组的四个时间戳列表。

我对第7行和第8行不感兴趣，即使orderId相同[因为它们没有按执行，持久，预订和删除的方式组合在一起]。

我可以通过分析函数来完成吗？

由于

Answer 1

不是很优雅，但是工作查询：

with t1 as (
  select tstamp ts, status st, orderid oid, 
      decode(status, 'Execute', 1, 'Persist', 2, 'Book', 3, 'Delete', 4, 5) ds
    from temp_table),
t2 as (
  select ts, st, oid, ds
    , decode(ds, 1, 1, lag(ds, ds-1) 
        over (partition by oid, trunc(ts) order by ts, ds)) d1
    , case when ds = 1 then lead(ds) over (partition by oid, trunc(ts) order by ts, ds)
           when ds = 2 then 2
           when ds = 3 then lag(ds) over (partition by oid, trunc(ts) order by ts, ds)
           when ds = 4 then lag(ds, 2) over (partition by oid, trunc(ts) order by ts, ds)
      end d2
    , case when ds = 1 then lead(ds, 2) over (partition by oid, trunc(ts) order by ts, ds)
           when ds = 2 then lead(ds) over (partition by oid, trunc(ts) order by ts, ds)
           when ds = 3 then 3
           when ds = 4 then lag(ds) over (partition by oid, trunc(ts) order by ts, ds)
      end d3
    , decode(ds, 4, 4, lead(ds, 4-ds) 
        over (partition by oid, trunc(ts) order by ts, ds)) d4
  from t1 )
select ts, st, oid from t2
  where (d1, d2, d3, d4) in ((1, 2, 3, 4))
  order by oid, ts, ds

如何从Oracle表中选择行组？

1 个答案: