Question

所以我有一张桌子上有球员数据（名字，球队等等）和一张有进球的球员（得分球员，本地球队等......）。我需要做的是，从每支球队获得最高分。所以我得到的结果是：

德国 - 无论名称 - 1
德国 - 另一个家伙 - 5
西班牙 - 另一个名字 - 8
意大利 - 另一个名字 - 6

正如你可以看到球队重复，我希望他们不重复，只是获得每支球队的最高得分手。

现在我有这个：

SELECT  P.TEAM_PLAYER, G.PLAYER_GOAL, COUNT(*) AS "TOTAL GOALS" FROM PLAYER P, GOAL G
WHERE TO_CHAR(G.DATE_GOAL, 'YYYY')=2002
AND P.NAME = G.PLAYER_GOAL
GROUP BY G.PLAYER_GOAL, P.TEAM_PLAYER
HAVING COUNT(*)>=ALL (SELECT COUNT(*) FROM PLAYER P2 where P.TEAM_PLAYER = P2.TEAM_PLAYER GROUP BY P2.TEAM_PLAYER)
ORDER BY COUNT(*) DESC;

我100％肯定我已经接近了，而且我非常确定我必须使用HAVING功能做到这一点，但我无法做到这一点。

如果没有HAVING，它会返回所有球员，他们的球队以及他们进球数目的列表，现在我想将其减少到每个球队只有一名球员。

PD：GOAL表中的团队是本地和访问团队，所以我必须使用Player表来获得团队。此外，目标表不是球员名单和他们有多少进球数，而是每个目标和进球得分的名单。

Answer 1

如果我理解正确，您可以尝试此查询。

只获取MAX列的PLAYER_GOAL，SUM(G.PLAYER_GOAL)代替COUNT(*)

SELECT  P.TEAM_PLAYER, 
        MAX(G.PLAYER_GOAL) "PLAYER_GOAL", 
        SUM(G.PLAYER_GOAL) AS "TOTAL GOALS" 
FROM PLAYER P 
INNER JOIN GOAL G 
ON P.NAME = G.PLAYER_NAME
WHERE TO_CHAR(G.DATE_GOAL, 'YYYY')=2002
GROUP BY P.TEAM_PLAYER
ORDER BY SUM(G.PLAYER_GOAL) DESC;

注意：

避免使用逗号到join表，这是旧的join样式，您可以使用内部联接。

修改

我不知道您的表架构，但此查询可能有效。

使用子查询来包含当前结果集。然后获取MAX函数和GROUP BY

SELECT T.TEAM_PLAYER, T.PLAYER_GOAL, MAX(TOTAL_GOALS) AS "TOTAL GOALS" FROM ( SELECT P.TEAM_PLAYER, G.PLAYER_GOAL, COUNT(*) AS "TOTAL_GOALS" FROM PLAYER P, GOAL G WHERE TO_CHAR(G.DATE_GOAL, 'YYYY')=2002 AND P.NAME = G.PLAYER_GOAL GROUP BY G.PLAYER_GOAL, P.TEAM_PLAYER HAVING COUNT(*)>=ALL (SELECT COUNT(*) FROM PLAYER P2 where P.TEAM_PLAYER = P2.TEAM_PLAYER GROUP BY P2.TEAM_PLAYER) ) T GROUP BY T.TEAM_PLAYER, T.PLAYER_GOAL ORDER BY MAX(TOTAL_GOALS) DESC

如何从不同的组中选择最高计数属性？

1 个答案: