假设我有startDate = 7/16/2015和endDate = 7/20/2015。这2个日期存储在SharePoint列表中。
如果用户在SharePoint列表中选择具有日期的确切日期,则可以计算总天数= 2,这意味着在其他日期不计算。
有人可以帮忙吗?
我使用以下代码计算差异的总天数,而不计算周末。但我无法弄清楚如何计算所选日期的总天数而不计算其他日期。
function workingDaysBetweenDates(startDate,endDate) {
// Validate input
if (endDate < startDate)
return 'Invalid !';
// Calculate days between dates
var millisecondsPerDay = 86400 * 1000; // Day in milliseconds
startDate.setHours(0,0,0,1); // Start just after midnight
endDate.setHours(23,59,59,999); // End just before midnight
var diff = endDate - startDate; // Milliseconds between datetime objects
var days = Math.ceil(diff / millisecondsPerDay);
// Subtract two weekend days for every week in between
var weeks = Math.floor(days / 7);
var days = days - (weeks * 2);
// Handle special cases
var startDay = startDate.getDay();
var endDay = endDate.getDay();
// Remove weekend not previously removed.
if (startDay - endDay > 1)
days = days - 2;
// Remove start day if span starts on Sunday but ends before Saturday
if (startDay == 0 && endDay != 6)
days = days - 1;
// Remove end day if span ends on Saturday but starts after Sunday
if (endDay == 6 && startDay != 0)
days = days - 1;
return days;
}
答案 0 :(得分:18)
以下函数计算两个日期之间的工作日数
function getBusinessDatesCount(startDate, endDate) {
var count = 0;
var curDate = startDate;
while (curDate <= endDate) {
var dayOfWeek = curDate.getDay();
if(!((dayOfWeek == 6) || (dayOfWeek == 0)))
count++;
curDate.setDate(curDate.getDate() + 1);
}
return count;
}
//Usage
var startDate = new Date('7/16/2015');
var endDate = new Date('7/20/2015');
var numOfDates = getBusinessDatesCount(startDate,endDate);
$('div#result').text(numOfDates);
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div id="result"/>
答案 1 :(得分:1)
首先,您必须计算时间差异,然后将时间转换为天数
var calculateDifference = function(date1, date2){
var timeDifference = Math.abs(date2.getTime() - date1.getTime());
return Math.ceil(timeDifference / (1000 * 3600 * 24));//ms * seconds * hours
}
var difference = calculateDifference(new Date("7/16/2015"), new Date("7/20/2015"));
未经测试,但应该有效......
答案 2 :(得分:0)
使用moment startDate
和endDate
:
function getBusinessDaysCount(startDate, endDate) {
let relativeDaySequence = [...Array(endDate.diff(startDate, "days")).keys()];
let daySequence = relativeDaySequence.map(relativeDay => {
let startDateClone = startDate.clone();
return startDateClone.add(relativeDay, "days");
});
return daySequence.reduce(
(dayCount, currentDay) => dayCount + (currentDay.day() === 0 || currentDay.day() === 6 ? 0 : 1),
0
);
}
答案 3 :(得分:-1)
可以试试这个也行。
for view in tableView.subviews {
if view is UIScrollView {
(view as? UIScrollView)!.delaysContentTouches = false
break
}
}