我有以下数据框
tdf <- structure(list(GO = c("Cytokine-cytokine receptor interaction",
"Cytokine-cytokine receptor interaction|Endocytosis", "I-kappaB kinase/NF-kappaB signaling",
"NF-kappa B signaling pathway", "NF-kappaB import into nucleus",
"T cell chemotaxis"), PosCount = c(17, 18, 4, 5, 1, 2), shortgo = structure(c(7L,
7L, 18L, 18L, 18L, 21L), .Label = c("TNF", "adaptive", "alpha",
"apop", "beta", "chemokine", "cytokine", "death", "defense",
"gamma", "immune response", "infla", "interleukin-1 ", "interleukin-10 ",
"interleukin-12 ", "interleukin-18 ", "interleukin-6 ", "kappa",
"migration", "stress", "taxis", "wound"), class = "factor")), .Names = c("GO",
"PosCount", "shortgo"), class = "data.frame", row.names = c(NA,
6L))
看起来像这样:
> tdf
GO PosCount shortgo
1 Cytokine-cytokine receptor interaction 17 cytokine
2 Cytokine-cytokine receptor interaction|Endocytosis 18 cytokine
3 I-kappaB kinase/NF-kappaB signaling 4 kappa
4 NF-kappa B signaling pathway 5 kappa
5 NF-kappaB import into nucleus 1 kappa
6 T cell chemotaxis 2 taxis
我想要做的是根据shortgo
拆分数据框,然后按GO
对其PosCount
成员进行排序,产生此结果(手工制作):
$cytokine
[1] Cytokine-cytokine receptor interaction|Endocytosis
[2] Cytokine-cytokine receptor interaction
$kappa
[1] NF-kappa B signaling pathway
[2] I-kappaB kinase/NF-kappaB signaling
[3] NF-kappaB import into nucleus
$taxis
[1] T cell chemotaxis
我坚持这个:
> split(tdf$GO,tdf$shortgo)
Error in split.default(tdf$GO, tdf$hsortgo) :
group length is 0 but data length > 0
我该怎么办呢?
答案 0 :(得分:5)
您可以在拆分之前先订购数据框:
library(dplyr)
tdf <- tdf %>% group_by(shortgo) %>% arrange(desc(PosCount))
然后拆分:
ldf <- split(tdf$GO, tdf$shortgo, drop=TRUE)
给出了所需的(有序)输出:
> ldf
$cytokine
[1] "Cytokine-cytokine receptor interaction|Endocytosis"
[2] "Cytokine-cytokine receptor interaction"
$kappa
[1] "NF-kappa B signaling pathway"
[2] "I-kappaB kinase/NF-kappaB signaling"
[3] "NF-kappaB import into nucleus"
$taxis
[1] "T cell chemotaxis"
如果要将数据框拆分为数据框列表,可以使用:
ldf <- split(tdf, tdf$shortgo, drop=TRUE)
基础R(provided by @Henrik in the comments)的解决方案:
split(tdf$GO[order(tdf$shortgo, -tdf$PosCount)], tdf$shortgo, drop=TRUE)
答案 1 :(得分:2)
使用data.table
,您可以使用setorder()
to reorder your data.table by reference,然后按如下方式分组:
require(data.table)
ans = setorder(setDT(tdf), shortgo, -GO)[, .(GO_list = list(GO)), by=shortgo]
我建议保留它,因为它更容易执行计算。但如果你坚持你的最终结构,那么你可以这样做:
ans = setattr(ans$GO_list, 'names', as.character(ans$shortgo))
如果您不希望通过引用重新排序原始数据,可以执行以下操作:
ans = setDT(tdf)[order(shortgo, -GO), .(GO_list = list(GO)), by=shortgo]