这是我用来存储图像的方法。
private String saveImage (Context context, String name, Bitmap image){
ContextWrapper cw = new ContextWrapper(context);
File dirImages = cw.getDir(Imagenes, Context.MODE_PRIVATE);
File myPath = new File(dirImages, name + .png);
FileOutputStream fos = null;
try{
fos = new FileOutputStream(myPath);
image.compress(Bitmap.CompressFormat.JPEG, 10, fos);
fos.flush();
}catch (FileNotFoundException ex){
ex.printStackTrace();
}catch (IOException ex){
ex.printStackTrace();
}
return myPath.getAbsolutePath();
}
如何适应存储音频和视频?
答案 0 :(得分:0)
尝试使用此代码段:
public static final int MEDIA_TYPE_IMAGE = 1;
public static final int MEDIA_TYPE_VIDEO = 2;
public static final int MEDIA_TYPE_AUDIO = 3;
/** Create a File for saving an image, video or audio */
public static File getOutputMediaFile(int type){
// To be safe, you should check that the SDCard is mounted
// using Environment.getExternalStorageState() before doing this.
File mediaStorageDir = new File(Environment.getExternalStoragePublicDirectory(
Environment.DIRECTORY_PICTURES), "App");
// This locat ion works best if you want the created images to be shared
// between applications and persist after your app has been uninstalled.
// Create the storage directory if it does not exist
if (!mediaStorageDir.exists()) {
if (!mediaStorageDir.mkdirs()) {
android.util.Log.d("log", "failed to create directory");
return null;
}
}
// Create a media file name
File mediaFile;
if (type == MEDIA_TYPE_IMAGE) {
mediaFile = new File(mediaStorageDir.getPath() + File.separator +
"IMG_"+ "PhotoTemp" + ".png");
} else if(type == MEDIA_TYPE_VIDEO) {
mediaFile = new File(mediaStorageDir.getPath() + File.separator +
"VID_"+ "VideoTemp" + ".mp4");
}
else if(type == MEDIA_TYPE_AUDIO) {
mediaFile = new File(mediaStorageDir.getPath() + File.separator +
"AUD_"+ "AudioTemp" + ".mp3");
}
else {
return null;
}
return mediaFile;
}
然后:
File mediaFile = getOutputMediaFile(MEDIA_TYPE_AUDIO);
if (mediaFile == null) {
android.util.Log.d("log", "Error creating media file, check storage permissions");
return null;
}
FileOutputStream fos = new FileOutputStream(mediaFile);
fos.write(data); //where data is byte[]
fos.close();
答案 1 :(得分:0)
虽然你可能在字节缓冲区中以块的形式从服务器下载,但是立即将每个块写入文件