Question

我收到此错误：变量数量与预准备语句中的参数数量不匹配我想我已经正确地写了声明，参数的数量也是一样的。请纠正我。

function Hello($questionId){
    global $mysqli,$db_table_prefix;
    $stmt = $mysqli->prepare("
        SELECT 
        id,
        answerby ,
        answer,
        questionId
        FROM ".$db_table_prefix."answers 
        WHERE `questionid` = 1
        ");
    $stmt->bind_param("s",$questionId);
    $stmt->execute();
    $stmt->bind_result($id, $answerby, $answer,$questionId);
    while ($stmt->fetch()){
        $row = array('id' => $id, 'answerby' => $answerby, 'answer' => $answer, 'questionId' => $questionId);
    }
    $stmt->close();
    return $row;

}

Answer 1

我编辑了代码，以便它可以工作。

函数Hello（$ questionId）{

    global $mysqli,$db_table_prefix;

    $stmt = $mysqli->prepare("
        SELECT 
        id,
        answerby ,
        answer,
        questionId
        FROM ".$db_table_prefix."answers 
        WHERE `questionid` = ?
        ");

    $stmt->bind_param("i",$questionId);
    $stmt->execute();

    $stmt->bind_result($id, $answerby, $answer,$questionId);

    while ($stmt->fetch()){

        $row = array('id' => $id, 'answerby' => $answerby, 'answer' => $answer, 'questionId' => $questionId);

    }

    $stmt->close();
    return $row;

}

获得以下错误：变量数量与预准备语句中的参数数量不匹配

1 个答案: