Question

我正在尝试通过准备查询并执行的函数传递准备好的查询，但我不断收到“Number of variables doesn't match number of parameters in prepared statement”。

我无法弄清楚什么是错的，因为我有与参数相同数量的变量。

查询：

UPDATE `users` SET fullname = ?,  telephone = ?,  email = ?,  company_name = ?,  company_addr2 = ?,  company_town = ?,  company_postcode = ?,  sra_registration = ?,  company_number = ?,  vat_registration = ?,  company_website = ?,  list_of_partners = ?,  my_staff = ? WHERE id = ?

PARAMS：

Array
        (
            [0] => Ben Shepherd
            [1] => 071111111111
            [2] => john.doe@domain.com
            [3] => Company name
            [4] => addr2
            [5] => town
            [6] => postcode
            [7] => 123456
            [8] => 123456
            [9] => 123465
            [10] => http://www.somewebsite.com
            [11] => United Kingdom
            [12] => "[{\\\"staff_firstname\\\":\\\"John\\\",\\\"staff_surname\\\":\\\"Smith\\\",\\\"staff_email\\\":\\\"some@email.com\\\"},{\\\"staff_firstname\\\":\\\"Jane\\\",\\\"staff_surname\\\":\\\"Smith\\\",\\\"staff_email\\\":\\\"some2@email.com\\\"},{\\\"staff_firstname\\\":\\\"John 3\\\",\\\"staff_surname\\\":\\\"Smith 3\\\",\\\"staff_email\\\":\\\"john.smith3@email.com\\\"}]"
            [13] => 1
)

查询功能：

    public static function query($query, $params = array())
    {           
        $params = !is_array($params) ? array($params) : $params;
        $data = array();

        $stmt = self::$i->prepare($query);

        if(!$stmt)
            return false;

        foreach($params as $value)
        {
            /* Bind parameters. Types: s = string, i = integer, d = double,  b = blob */
            switch( true )
            {
                case (is_double($value)):
                    $type = 'd';
                    break;

                case (is_int($value)):
                    $type = 'i';
                    break;

                default:
                case (is_string($value)):
                    $type = 's';
                    break;
            }
            $stmt->bind_param($type, $value);
        }

        $stmt->execute();
        $res = $stmt->get_result();

        if(!$res) return false;

        while($row = $res->fetch_array(MYSQLI_ASSOC) )
        {
            $data[] = $row;
        }

        self::$customError = "";

        return $data;
    }

Answer 1

尝试将所有参数放入一个bind_param来电。

使用call_user_func_array：

将$stmt->bind_param($type, $value);移出foreach循环

<?php

public static function query($query, $params = array())
{           
    $params = !is_array($params) ? array($params) : $params;
    ...

    $types = array();
    foreach($params as $value)
    {
        /* Bind parameters. Types: s = string, i = integer, d = double,  b = blob */
        switch( true )
        {
            case (is_double($value)):
                $type = 'd';
                break;

            case (is_int($value)):
                $type = 'i';
                break;

            default:
            case (is_string($value)):
                $type = 's';
                break;
        }

        $types .= $type;
    }

    call_user_func_array(array($stmt, 'bind_param'), array_merge(array($types), $params));

MySQLi：变量数与预准备语句中的参数数量不匹配

1 个答案: